fix 修复 不同类别菜单的判断逻辑有误问题

This commit is contained in:
疯狂的狮子Li
2026-01-21 11:46:33 +08:00
parent 79d9f47053
commit aa277b373b

View File

@@ -377,21 +377,24 @@ public class SysMenuServiceImpl implements ISysMenuService {
List<SysMenu> sysMenuList = baseMapper.selectList(
new LambdaQueryWrapper<SysMenu>()
.in(SysMenu::getMenuType, SystemConstants.TYPE_DIR, SystemConstants.TYPE_MENU)
.eq(SysMenu::getPath, path).or().eq(SysMenu::getPath, routeName));
.and(w ->
w.eq(SysMenu::getPath, path).or().eq(SysMenu::getPath, routeName)
));
for (SysMenu sysMenu : sysMenuList) {
if (sysMenu.getMenuId() != menuId) {
if (!sysMenu.getMenuId().equals(menuId)) {
Long dbParentId = sysMenu.getParentId();
String dbPath = sysMenu.getPath();
String dbRouteName = StringUtils.isEmpty(sysMenu.getRouteName()) ? dbPath : sysMenu.getRouteName();
if (StringUtils.equalsAnyIgnoreCase(path, dbPath) && parentId.longValue() == dbParentId.longValue()) {
if (StringUtils.equalsAnyIgnoreCase(path, dbPath) && parentId.equals(dbParentId)) {
log.warn("[同级路由冲突] 同级下已存在相同路由路径 '{}',冲突菜单:{}", dbPath, sysMenu.getMenuName());
return false;
} else if (StringUtils.equalsAnyIgnoreCase(path, dbPath)
&& parentId.longValue() == Constants.TOP_PARENT_ID
&& dbParentId.longValue() == Constants.TOP_PARENT_ID) {
&& Constants.TOP_PARENT_ID.equals(parentId)
&& Constants.TOP_PARENT_ID.equals(dbParentId)) {
log.warn("[根目录路由冲突] 根目录下路由 '{}' 必须唯一,已被菜单 '{}' 占用", path, sysMenu.getMenuName());
return false;
} else if (StringUtils.equalsAnyIgnoreCase(routeName, dbRouteName)) {
} else if (StringUtils.equalsAnyIgnoreCase(routeName, dbRouteName)
&& sysMenu.getMenuType().equals(menu.getMenuType())) {
log.warn("[路由名称冲突] 路由名称 '{}' 需全局唯一,已被菜单 '{}' 使用", routeName, sysMenu.getMenuName());
return false;
}