This commit is contained in:
krahets
2023-11-09 05:13:48 +08:00
parent 9701430089
commit 0105644232
83 changed files with 516 additions and 509 deletions
@@ -8,7 +8,7 @@ comments: true
给定一个二叉树的前序遍历 `preorder` 和中序遍历 `inorder` ,请从中构建二叉树,返回二叉树的根节点。假设二叉树中没有值重复的节点。
![构建二叉树的示例数据](build_binary_tree_problem.assets/build_tree_example.png)
![构建二叉树的示例数据](build_binary_tree_problem.assets/build_tree_example.png){ class="animation-figure" }
<p align="center"> 图 12-5 &nbsp; 构建二叉树的示例数据 </p>
@@ -35,7 +35,7 @@ comments: true
2. 查找根节点 3 在 `inorder` 中的索引,利用该索引可将 `inorder` 划分为 `[ 9 | 3 1 2 7 ]`
3. 根据 `inorder` 划分结果,易得左子树和右子树的节点数量分别为 1 和 3 ,从而可将 `preorder` 划分为 `[ 3 | 9 | 2 1 7 ]`
![在前序和中序遍历中划分子树](build_binary_tree_problem.assets/build_tree_preorder_inorder_division.png)
![在前序和中序遍历中划分子树](build_binary_tree_problem.assets/build_tree_preorder_inorder_division.png){ class="animation-figure" }
<p align="center"> 图 12-6 &nbsp; 在前序和中序遍历中划分子树 </p>
@@ -63,7 +63,7 @@ comments: true
请注意,右子树根节点索引中的 $(m-l)$ 的含义是“左子树的节点数量”,建议配合图 12-7 理解。
![根节点和左右子树的索引区间表示](build_binary_tree_problem.assets/build_tree_division_pointers.png)
![根节点和左右子树的索引区间表示](build_binary_tree_problem.assets/build_tree_division_pointers.png){ class="animation-figure" }
<p align="center"> 图 12-7 &nbsp; 根节点和左右子树的索引区间表示 </p>
@@ -448,37 +448,37 @@ comments: true
图 12-8 展示了构建二叉树的递归过程,各个节点是在向下“递”的过程中建立的,而各条边(即引用)是在向上“归”的过程中建立的。
=== "<1>"
![构建二叉树的递归过程](build_binary_tree_problem.assets/built_tree_step1.png)
![构建二叉树的递归过程](build_binary_tree_problem.assets/built_tree_step1.png){ class="animation-figure" }
=== "<2>"
![built_tree_step2](build_binary_tree_problem.assets/built_tree_step2.png)
![built_tree_step2](build_binary_tree_problem.assets/built_tree_step2.png){ class="animation-figure" }
=== "<3>"
![built_tree_step3](build_binary_tree_problem.assets/built_tree_step3.png)
![built_tree_step3](build_binary_tree_problem.assets/built_tree_step3.png){ class="animation-figure" }
=== "<4>"
![built_tree_step4](build_binary_tree_problem.assets/built_tree_step4.png)
![built_tree_step4](build_binary_tree_problem.assets/built_tree_step4.png){ class="animation-figure" }
=== "<5>"
![built_tree_step5](build_binary_tree_problem.assets/built_tree_step5.png)
![built_tree_step5](build_binary_tree_problem.assets/built_tree_step5.png){ class="animation-figure" }
=== "<6>"
![built_tree_step6](build_binary_tree_problem.assets/built_tree_step6.png)
![built_tree_step6](build_binary_tree_problem.assets/built_tree_step6.png){ class="animation-figure" }
=== "<7>"
![built_tree_step7](build_binary_tree_problem.assets/built_tree_step7.png)
![built_tree_step7](build_binary_tree_problem.assets/built_tree_step7.png){ class="animation-figure" }
=== "<8>"
![built_tree_step8](build_binary_tree_problem.assets/built_tree_step8.png)
![built_tree_step8](build_binary_tree_problem.assets/built_tree_step8.png){ class="animation-figure" }
=== "<9>"
![built_tree_step9](build_binary_tree_problem.assets/built_tree_step9.png)
![built_tree_step9](build_binary_tree_problem.assets/built_tree_step9.png){ class="animation-figure" }
<p align="center"> 图 12-8 &nbsp; 构建二叉树的递归过程 </p>
每个递归函数内的前序遍历 `preorder` 和中序遍历 `inorder` 的划分结果如图 12-9 所示。
![每个递归函数中的划分结果](build_binary_tree_problem.assets/built_tree_overall.png)
![每个递归函数中的划分结果](build_binary_tree_problem.assets/built_tree_overall.png){ class="animation-figure" }
<p align="center"> 图 12-9 &nbsp; 每个递归函数中的划分结果 </p>