This commit is contained in:
krahets
2024-04-03 21:48:54 +08:00
parent d5a7899137
commit 0a9daa8b9f
11 changed files with 685 additions and 97 deletions
@@ -193,7 +193,16 @@ comments: true
=== "Ruby"
```ruby title=""
# 在某运行平台下
def algorithm(n)
a = 2 # 1 ns
a = a + 1 # 1 ns
a = a * 2 # 10 ns
# 循环 n 次
(n...0).each do # 1 ns
puts 0 # 5 ns
end
end
```
=== "Zig"
@@ -478,7 +487,20 @@ $$
=== "Ruby"
```ruby title=""
# 算法 A 的时间复杂度:常数阶
def algorithm_A(n)
puts 0
end
# 算法 B 的时间复杂度:线性阶
def algorithm_B(n)
(0...n).each { puts 0 }
end
# 算法 C 的时间复杂度:常数阶
def algorithm_C(n)
(0...1_000_000).each { puts 0 }
end
```
=== "Zig"
@@ -694,7 +716,15 @@ $$
=== "Ruby"
```ruby title=""
def algorithm(n)
a = 1 # +1
a = a + 1 # +1
a = a * 2 # +1
# 循环 n 次
(0...n).each do # +1
puts 0 # +1
end
end
```
=== "Zig"
@@ -978,7 +1008,16 @@ $T(n)$ 是一次函数,说明其运行时间的增长趋势是线性的,因
=== "Ruby"
```ruby title=""
def algorithm(n)
a = 1 # +0(技巧 1
a = a + n # +0(技巧 1
# +n(技巧 2
(0...(5 * n + 1)).each do { puts 0 }
# +n*n(技巧 3
(0...(2 * n)).each do
(0...(n + 1)).each do { puts 0 }
end
end
```
=== "Zig"
@@ -1216,7 +1255,15 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{constant}
### 常数阶 ###
def constant(n)
count = 0
size = 100000
(0...size).each { count += 1 }
count
end
```
=== "Zig"
@@ -1394,7 +1441,12 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{linear}
### 线性阶 ###
def linear(n)
count = 0
(0...n).each { count += 1 }
count
end
```
=== "Zig"
@@ -1587,7 +1639,17 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{array_traversal}
### 线性阶(遍历数组)###
def array_traversal(nums)
count = 0
# 循环次数与数组长度成正比
for num in nums
count += 1
end
count
end
```
=== "Zig"
@@ -1807,7 +1869,19 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{quadratic}
### 平方阶 ###
def quadratic(n)
count = 0
# 循环次数与数据大小 n 成平方关系
for i in 0...n
for j in 0...n
count += 1
end
end
count
end
```
=== "Zig"
@@ -2113,7 +2187,26 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{bubble_sort}
### 平方阶(冒泡排序)###
def bubble_sort(nums)
count = 0 # 计数器
# 外循环:未排序区间为 [0, i]
for i in (nums.length - 1).downto(0)
# 内循环:将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
for j in 0...i
if nums[j] > nums[j + 1]
# 交换 nums[j] 与 nums[j + 1]
tmp = nums[j]
nums[j] = nums[j + 1]
nums[j + 1] = tmp
count += 3 # 元素交换包含 3 个单元操作
end
end
end
count
end
```
=== "Zig"
@@ -2375,7 +2468,19 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{exponential}
### 指数阶(循环实现)###
def exponential(n)
count, base = 0, 1
# 细胞每轮一分为二,形成数列 1, 2, 4, 8, ..., 2^(n-1)
(0...n).each do
(0...base).each { count += 1 }
base *= 2
end
# count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
count
end
```
=== "Zig"
@@ -2544,7 +2649,11 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{exp_recur}
### 指数阶(递归实现)###
def exp_recur(n)
return 1 if n == 1
exp_recur(n - 1) + exp_recur(n - 1) + 1
end
```
=== "Zig"
@@ -2741,7 +2850,17 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{logarithmic}
### 对数阶(循环实现)###
def logarithmic(n)
count = 0
while n > 1
n /= 2
count += 1
end
count
end
```
=== "Zig"
@@ -2904,7 +3023,11 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{log_recur}
### 对数阶(递归实现)###
def log_recur(n)
return 0 unless n > 1
log_recur(n / 2) + 1
end
```
=== "Zig"
@@ -3118,7 +3241,15 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{linear_log_recur}
### 线性对数阶 ###
def linear_log_recur(n)
return 1 unless n > 1
count = linear_log_recur(n / 2) + linear_log_recur(n / 2)
(0...n).each { count += 1 }
count
end
```
=== "Zig"
@@ -3350,7 +3481,16 @@ $$
=== "Ruby"
```ruby title="time_complexity.rb"
[class]{}-[func]{factorial_recur}
### 阶乘阶(递归实现)###
def factorial_recur(n)
return 1 if n == 0
count = 0
# 从 1 个分裂出 n 个
(0...n).each { count += factorial_recur(n - 1) }
count
end
```
=== "Zig"
@@ -3745,9 +3885,24 @@ $$
=== "Ruby"
```ruby title="worst_best_time_complexity.rb"
[class]{}-[func]{random_numbers}
### 生成一个数组,元素为: 1, 2, ..., n ,顺序被打乱 ###
def random_numbers(n)
# 生成数组 nums =: 1, 2, 3, ..., n
nums = Array.new(n) { |i| i + 1 }
# 随机打乱数组元素
nums.shuffle!
end
[class]{}-[func]{find_one}
### 查找数组 nums 中数字 1 所在索引 ###
def find_one(nums)
for i in 0...nums.length
# 当元素 1 在数组头部时,达到最佳时间复杂度 O(1)
# 当元素 1 在数组尾部时,达到最差时间复杂度 O(n)
return i if nums[i] == 1
end
-1
end
```
=== "Zig"