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krahets
2023-02-26 01:51:44 +08:00
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2. 同理,对剩余 $n - 1$ 个元素执行「冒泡」,可将第二大元素交换至正确位置,因而待排序元素只剩 $n - 2$ 个。
3. 以此类推…… **循环 $n - 1$ 轮「冒泡」,即可完成整个数组的排序**
![bubble_sort](bubble_sort.assets/bubble_sort.png)
![bubble_sort_overview](bubble_sort.assets/bubble_sort_overview.png)
<p align="center"> Fig. 冒泡排序流程 </p>