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Translate all code to English (#1836)
* Review the EN heading format. * Fix pythontutor headings. * Fix pythontutor headings. * bug fixes * Fix headings in **/summary.md * Revisit the CN-to-EN translation for Python code using Claude-4.5 * Revisit the CN-to-EN translation for Java code using Claude-4.5 * Revisit the CN-to-EN translation for Cpp code using Claude-4.5. * Fix the dictionary. * Fix cpp code translation for the multipart strings. * Translate Go code to English. * Update workflows to test EN code. * Add EN translation for C. * Add EN translation for CSharp. * Add EN translation for Swift. * Trigger the CI check. * Revert. * Update en/hash_map.md * Add the EN version of Dart code. * Add the EN version of Kotlin code. * Add missing code files. * Add the EN version of JavaScript code. * Add the EN version of TypeScript code. * Fix the workflows. * Add the EN version of Ruby code. * Add the EN version of Rust code. * Update the CI check for the English version code. * Update Python CI check. * Fix cmakelists for en/C code. * Fix Ruby comments
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/**
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* File: binary_search_tree.kt
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* Created Time: 2024-01-25
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* Author: curtishd (1023632660@qq.com)
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*/
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package chapter_tree
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import utils.TreeNode
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import utils.printTree
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/* Binary search tree */
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class BinarySearchTree {
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// Initialize empty tree
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private var root: TreeNode? = null
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/* Get binary tree root node */
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fun getRoot(): TreeNode? {
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return root
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}
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/* Search node */
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fun search(num: Int): TreeNode? {
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var cur = root
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// Loop search, exit after passing leaf node
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while (cur != null) {
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// Target node is in cur's right subtree
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cur = if (cur._val < num)
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cur.right
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// Target node is in cur's left subtree
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else if (cur._val > num)
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cur.left
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// Found target node, exit loop
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else
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break
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}
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// Return target node
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return cur
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}
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/* Insert node */
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fun insert(num: Int) {
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// If tree is empty, initialize root node
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if (root == null) {
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root = TreeNode(num)
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return
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}
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var cur = root
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var pre: TreeNode? = null
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// Loop search, exit after passing leaf node
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while (cur != null) {
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// Found duplicate node, return directly
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if (cur._val == num)
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return
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pre = cur
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// Insertion position is in cur's right subtree
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cur = if (cur._val < num)
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cur.right
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// Insertion position is in cur's left subtree
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else
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cur.left
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}
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// Insert node
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val node = TreeNode(num)
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if (pre?._val!! < num)
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pre.right = node
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else
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pre.left = node
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}
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/* Remove node */
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fun remove(num: Int) {
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// If tree is empty, return directly
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if (root == null)
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return
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var cur = root
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var pre: TreeNode? = null
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// Loop search, exit after passing leaf node
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while (cur != null) {
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// Found node to delete, exit loop
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if (cur._val == num)
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break
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pre = cur
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// Node to delete is in cur's right subtree
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cur = if (cur._val < num)
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cur.right
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// Node to delete is in cur's left subtree
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else
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cur.left
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}
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// If no node to delete, return directly
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if (cur == null)
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return
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// Number of child nodes = 0 or 1
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if (cur.left == null || cur.right == null) {
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// When number of child nodes = 0 / 1, child = null / that child node
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val child = if (cur.left != null)
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cur.left
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else
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cur.right
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// Delete node cur
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if (cur != root) {
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if (pre!!.left == cur)
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pre.left = child
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else
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pre.right = child
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} else {
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// If deleted node is root node, reassign root node
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root = child
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}
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// Number of child nodes = 2
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} else {
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// Get next node of cur in inorder traversal
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var tmp = cur.right
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while (tmp!!.left != null) {
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tmp = tmp.left
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}
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// Recursively delete node tmp
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remove(tmp._val)
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// Replace cur with tmp
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cur._val = tmp._val
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}
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}
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}
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/* Driver Code */
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fun main() {
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/* Initialize binary search tree */
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val bst = BinarySearchTree()
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// Please note that different insertion orders will generate different binary trees, this sequence can generate a perfect binary tree
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val nums = intArrayOf(8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15)
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for (num in nums) {
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bst.insert(num)
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}
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println("\nInitialized binary tree is\n")
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printTree(bst.getRoot())
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/* Search node */
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val node = bst.search(7)
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println("Found node object is $node, node value = ${node?._val}")
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/* Insert node */
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bst.insert(16)
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println("\nAfter inserting node 16, binary tree is\n")
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printTree(bst.getRoot())
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/* Remove node */
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bst.remove(1)
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println("\nAfter removing node 1, binary tree is\n")
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printTree(bst.getRoot())
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bst.remove(2)
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println("\nAfter removing node 2, binary tree is\n")
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printTree(bst.getRoot())
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bst.remove(4)
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println("\nAfter removing node 4, binary tree is\n")
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printTree(bst.getRoot())
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}
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