Translate all code to English (#1836)

* Review the EN heading format.

* Fix pythontutor headings.

* Fix pythontutor headings.

* bug fixes

* Fix headings in **/summary.md

* Revisit the CN-to-EN translation for Python code using Claude-4.5

* Revisit the CN-to-EN translation for Java code using Claude-4.5

* Revisit the CN-to-EN translation for Cpp code using Claude-4.5.

* Fix the dictionary.

* Fix cpp code translation for the multipart strings.

* Translate Go code to English.

* Update workflows to test EN code.

* Add EN translation for C.

* Add EN translation for CSharp.

* Add EN translation for Swift.

* Trigger the CI check.

* Revert.

* Update en/hash_map.md

* Add the EN version of Dart code.

* Add the EN version of Kotlin code.

* Add missing code files.

* Add the EN version of JavaScript code.

* Add the EN version of TypeScript code.

* Fix the workflows.

* Add the EN version of Ruby code.

* Add the EN version of Rust code.

* Update the CI check for the English version  code.

* Update Python CI check.

* Fix cmakelists for en/C code.

* Fix Ruby comments
This commit is contained in:
Yudong Jin
2025-12-31 07:44:52 +08:00
committed by GitHub
parent 45e1295241
commit 2778a6f9c7
1284 changed files with 71557 additions and 3275 deletions
@@ -0,0 +1,42 @@
=begin
File: binary_search_recur.rb
Created Time: 2024-05-13
Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
=end
### Binary search: problem f(i, j) ###
def dfs(nums, target, i, j)
# If the interval is empty, it means there is no target element, return -1
return -1 if i > j
# Calculate the midpoint index m
m = (i + j) / 2
if nums[m] < target
# Recursion subproblem f(m+1, j)
return dfs(nums, target, m + 1, j)
elsif nums[m] > target
# Recursion subproblem f(i, m-1)
return dfs(nums, target, i, m - 1)
else
# Found the target element, return its index
return m
end
end
### Binary search ###
def binary_search(nums, target)
n = nums.length
# Solve the problem f(0, n-1)
dfs(nums, target, 0, n - 1)
end
### Driver Code ###
if __FILE__ == $0
target = 6
nums = [1, 3, 6, 8, 12, 15, 23, 26, 31, 35]
# Binary search (closed interval on both sides)
index = binary_search(nums, target)
puts "Index of target element 6 is #{index}"
end
@@ -0,0 +1,46 @@
=begin
File: build_tree.rb
Created Time: 2024-05-13
Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
=end
require_relative '../utils/tree_node'
require_relative '../utils/print_util'
### Build binary tree: divide and conquer ###
def dfs(preorder, inorder_map, i, l, r)
# Terminate when the subtree interval is empty
return if r - l < 0
# Initialize the root node
root = TreeNode.new(preorder[i])
# Query m to divide the left and right subtrees
m = inorder_map[preorder[i]]
# Subproblem: build the left subtree
root.left = dfs(preorder, inorder_map, i + 1, l, m - 1)
# Subproblem: build the right subtree
root.right = dfs(preorder, inorder_map, i + 1 + m - l, m + 1, r)
# Return the root node
root
end
### Build binary tree ###
def build_tree(preorder, inorder)
# Initialize hash map, storing the mapping from inorder elements to indices
inorder_map = {}
inorder.each_with_index { |val, i| inorder_map[val] = i }
dfs(preorder, inorder_map, 0, 0, inorder.length - 1)
end
### Driver Code ###
if __FILE__ == $0
preorder = [3, 9, 2, 1, 7]
inorder = [9, 3, 1, 2, 7]
puts "Pre-order traversal = #{preorder}"
puts "In-order traversal = #{inorder}"
root = build_tree(preorder, inorder)
puts "The constructed binary tree is:"
print_tree(root)
end
@@ -0,0 +1,55 @@
=begin
File: hanota.rb
Created Time: 2024-05-13
Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
=end
### Move one disk ###
def move(src, tar)
# Take out a disk from the top of src
pan = src.pop
# Place the disk on top of tar
tar << pan
end
### Solve Tower of Hanoi f(i) ###
def dfs(i, src, buf, tar)
# If there is only one disk left in src, move it directly to tar
if i == 1
move(src, tar)
return
end
# Subproblem f(i-1): move the top i-1 disks from src to buf using tar
dfs(i - 1, src, tar, buf)
# Subproblem f(1): move the remaining disk from src to tar
move(src, tar)
# Subproblem f(i-1): move the top i-1 disks from buf to tar using src
dfs(i - 1, buf, src, tar)
end
### Solve Tower of Hanoi ###
def solve_hanota(_A, _B, _C)
n = _A.length
# Move the top n disks from A to C using B
dfs(n, _A, _B, _C)
end
### Driver Code ###
if __FILE__ == $0
# The tail of the list is the top of the rod
A = [5, 4, 3, 2, 1]
B = []
C = []
puts "In initial state:"
puts "A = #{A}"
puts "B = #{B}"
puts "C = #{C}"
solve_hanota(A, B, C)
puts "After disk movement is complete:"
puts "A = #{A}"
puts "B = #{B}"
puts "C = #{C}"
end