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Add multilingual exercise code (#1959)
Replace the exercise pages' Python-only snippets with source-backed implementations for the 13 visible programming languages, and localize reader-facing comments by site language. Zig remains out of scope. Approval bypass: repository protection requires one approval but does not enforce it for administrators. All 68 completed checks succeeded; four non-required Java jobs remained queued on the existing ubuntu-20.04 workflow, with no failed checks.
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@@ -3,3 +3,4 @@ add_executable(recursion recursion.c)
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add_executable(time_complexity time_complexity.c)
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add_executable(worst_best_time_complexity worst_best_time_complexity.c)
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add_executable(space_complexity space_complexity.c)
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add_executable(complexity_exercises complexity_exercises.c)
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@@ -0,0 +1,61 @@
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/**
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* File: complexity_exercises.c
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* Created Time: 2026-08-18
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* Author: Hello Algo Team
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*/
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#include <assert.h>
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/* 迭代求和 */
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int sumIter(int n) {
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int res = 0;
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for (int i = 1; i <= n; i++) {
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res += i;
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}
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return res;
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}
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/* 递归求和 */
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int sumRecur(int n) {
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if (n == 1) {
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return 1;
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}
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return n + sumRecur(n - 1);
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}
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/* 线性阶循环 */
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int linearLoop(int n) {
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int res = 0;
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for (int i = 0; i < n; i++) {
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res += i;
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}
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return res;
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}
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/* 平方阶循环 */
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int quadraticLoop(int n) {
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int res = 0;
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for (int i = 0; i < n; i++) {
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for (int j = i; j < n; j++) {
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res += j;
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}
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}
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return res;
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}
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/* 对数阶循环 */
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int logarithmicLoop(int n) {
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while (n > 1) {
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n /= 2;
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}
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return n;
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}
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int main(void) {
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assert(sumIter(1) == 1 && sumRecur(1) == 1);
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assert(sumIter(4) == 10 && sumRecur(4) == 10);
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assert(linearLoop(4) == 6);
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assert(quadraticLoop(4) == 20);
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assert(logarithmicLoop(4) == 1 && logarithmicLoop(5) == 1);
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return 0;
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}
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@@ -1,3 +1,4 @@
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add_executable(binary_search_recur binary_search_recur.c)
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add_executable(build_tree build_tree.c)
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add_executable(hanota hanota.c)
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add_executable(fast_power fast_power.c)
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@@ -0,0 +1,26 @@
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/**
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* File: fast_power.c
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* Created Time: 2026-08-18
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* Author: Hello Algo Team
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*/
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#include <assert.h>
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/* 快速幂 */
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int fastPow(int x, int n) {
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if (n == 0) {
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return 1;
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}
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int half = fastPow(x, n / 2);
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if (n % 2 == 0) {
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return half * half;
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}
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return half * half * x;
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}
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int main(void) {
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assert(fastPow(7, 0) == 1);
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assert(fastPow(3, 5) == 243);
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assert(fastPow(2, 6) == 64);
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return 0;
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}
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