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<p>如果感觉对复杂度分析的概念一知半解,无需担心,后续章节会展开介绍。</p>
<h2 id="213">2.1.3. &nbsp; 复杂度分析重要性<a class="headerlink" href="#213" title="Permanent link">&para;</a></h2>
<p>复杂度分析给出一把评价算法效率的“标尺”,告诉我们执行某个算法需要多少时间和空间资源,也让我们可以开展不同算法之间的效率对比。</p>
<p>计算复杂度是个数学概念,对于初学者可能比较抽象,学习难度相对较高。从这个角度出发,其并不适合作为第一章内容。但是,当我们讨论某个数据结构或者算法的特点时,难以避免需要分析它的运行速度和空间使用情况。<strong>因此,在展开学习数据结构与算法之前,建议读者先对计算复杂度建立起初步的了解,并且能够完成简单案例的复杂度分析</strong></p>
<p>复杂度是个数学概念,对于初学者可能比较抽象,学习难度相对较高。从这个角度出发,其并不适合作为第一章内容。但是,当我们讨论某个数据结构或者算法的特点时,难以避免需要分析它的运行速度和空间使用情况。<strong>因此,在展开学习数据结构与算法之前,建议读者先对复杂度建立起初步的了解,并且能够完成简单案例的复杂度分析</strong></p>
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<li class="md-nav__item">
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0.3. &nbsp; 编程环境安装
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<p>你可以假设每种输入只会对应一个答案。但是,数组中同一个元素在答案里不能重复出现。</p>
<p>你可以按任意顺序返回答案。</p>
</div>
<p>「暴力枚举」和「辅助哈希表」分别 <strong>空间最优</strong><strong>时间最优</strong> 的两种解法。本着时间比空间更宝贵的原则,后者是本题的最佳解法。</p>
<p>「暴力枚举」和「辅助哈希表」分别对应 <strong>空间最优</strong><strong>时间最优</strong> 的两种解法。本着时间比空间更宝贵的原则,后者是本题的最佳解法。</p>
<h3 id="_1">方法一:暴力枚举<a class="headerlink" href="#_1" title="Permanent link">&para;</a></h3>
<p>时间复杂度 <span class="arithmatex">\(O(N^2)\)</span> ,空间复杂度 <span class="arithmatex">\(O(1)\)</span> 属于「时间换空间」</p>
<p>虽然仅使用常数大小的额外空间,但运行速度过慢。</p>
<p>考虑直接遍历所有所有可能性。通过开启一个两层循环,判断两个整数的和是否为 <code>target</code> 若是则返回它俩的索引(即下标)即可</p>
<div class="tabbed-set tabbed-alternate" data-tabs="1:10"><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><input id="__tabbed_1_2" name="__tabbed_1" type="radio" /><input id="__tabbed_1_3" name="__tabbed_1" type="radio" /><input id="__tabbed_1_4" name="__tabbed_1" type="radio" /><input id="__tabbed_1_5" name="__tabbed_1" type="radio" /><input id="__tabbed_1_6" name="__tabbed_1" type="radio" /><input id="__tabbed_1_7" name="__tabbed_1" type="radio" /><input id="__tabbed_1_8" name="__tabbed_1" type="radio" /><input id="__tabbed_1_9" name="__tabbed_1" type="radio" /><input id="__tabbed_1_10" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">Java</label><label for="__tabbed_1_2">C++</label><label for="__tabbed_1_3">Python</label><label for="__tabbed_1_4">Go</label><label for="__tabbed_1_5">JavaScript</label><label for="__tabbed_1_6">TypeScript</label><label for="__tabbed_1_7">C</label><label for="__tabbed_1_8">C#</label><label for="__tabbed_1_9">Swift</label><label for="__tabbed_1_10">Zig</label></div>
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<p>该方法的时间复杂度为 <span class="arithmatex">\(O(N^2)\)</span> ,空间复杂度为 <span class="arithmatex">\(O(1)\)</span> <strong>属于时间换空间</strong>。本方法时间复杂度较高,在大数据量下非常耗时。</p>
<h3 id="_2">方法二:辅助哈希表<a class="headerlink" href="#_2" title="Permanent link">&para;</a></h3>
<p>时间复杂度 <span class="arithmatex">\(O(N)\)</span> ,空间复杂度 <span class="arithmatex">\(O(N)\)</span> 属于「空间换时间」。</p>
<p>借助辅助哈希表 dic ,通过保存数组元素与索引的映射来提升算法运行速度。</p>
<p>考虑借助一个哈希表,key 为数组元素、value 为元素索引。循环遍历数组中的每个元素 <code>num</code> 并执行:</p>
<ol>
<li>判断数字 <code>target - num</code> 是否在哈希表中,若是则直接返回该两个元素的索引;</li>
<li>将元素 <code>num</code> 和其索引添加进哈希表;</li>
</ol>
<div class="tabbed-set tabbed-alternate" data-tabs="2:10"><input checked="checked" id="__tabbed_2_1" name="__tabbed_2" type="radio" /><input id="__tabbed_2_2" name="__tabbed_2" type="radio" /><input id="__tabbed_2_3" name="__tabbed_2" type="radio" /><input id="__tabbed_2_4" name="__tabbed_2" type="radio" /><input id="__tabbed_2_5" name="__tabbed_2" type="radio" /><input id="__tabbed_2_6" name="__tabbed_2" type="radio" /><input id="__tabbed_2_7" name="__tabbed_2" type="radio" /><input id="__tabbed_2_8" name="__tabbed_2" type="radio" /><input id="__tabbed_2_9" name="__tabbed_2" type="radio" /><input id="__tabbed_2_10" name="__tabbed_2" type="radio" /><div class="tabbed-labels"><label for="__tabbed_2_1">Java</label><label for="__tabbed_2_2">C++</label><label for="__tabbed_2_3">Python</label><label for="__tabbed_2_4">Go</label><label for="__tabbed_2_5">JavaScript</label><label for="__tabbed_2_6">TypeScript</label><label for="__tabbed_2_7">C</label><label for="__tabbed_2_8">C#</label><label for="__tabbed_2_9">Swift</label><label for="__tabbed_2_10">Zig</label></div>
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<p>该方法的时间复杂度为 <span class="arithmatex">\(O(N)\)</span> ,空间复杂度为 <span class="arithmatex">\(O(N)\)</span> <strong>体现空间换时间</strong>。本方法虽然引入了额外空间使用,但时间和空间使用整体更加均衡,因此为本题最优解法。</p>
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<li class="md-nav__item">
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<p>相比直接统计算法运行时间,时间复杂度分析的做法有什么好处呢?以及有什么不足?</p>
<p><strong>时间复杂度可以有效评估算法效率</strong>。算法 <code>B</code> 运行时间的增长是线性的,在 <span class="arithmatex">\(n &gt; 1\)</span> 时慢于算法 <code>A</code> ,在 <span class="arithmatex">\(n &gt; 1000000\)</span> 时慢于算法 <code>C</code> 。实质上,只要输入数据大小 <span class="arithmatex">\(n\)</span> 足够大,复杂度为「常数阶」的算法一定优于「线性阶」的算法,这也正是时间增长趋势的含义。</p>
<p><strong>时间复杂度的推算方法更加简便</strong>。在时间复杂度分析中,我们可以将统计「计算操作的运行时间」简化为统计「计算操作的数量」,这是因为,无论是运行平台还是计算操作类型,都与算法运行时间的增长趋势无关。因而,我们可以简单地将所有计算操作的执行时间统一看作是相同的“单位时间”,这样的简化做法大大降低了估算难度。</p>
<p><strong>时间复杂度也存在一定的局限性</strong>。比如,虽然算法 <code>A</code><code>C</code> 的时间复杂度相同,但是实际的运行时间有非常大的差别。再比如,虽然算法 <code>B</code><code>C</code> 的时间复杂度要更高,但在输入数据大小 <span class="arithmatex">\(n\)</span> 比较小时,算法 <code>B</code> 是要明显优于算法 <code>C</code> 的。对于以上情况,我们很难仅凭时间复杂度来判定算法效率高低。然而,即使存在这些问题,计算复杂度仍然是评判算法效率的最有效且常用的方法。</p>
<p><strong>时间复杂度也存在一定的局限性</strong>。比如,虽然算法 <code>A</code><code>C</code> 的时间复杂度相同,但是实际的运行时间有非常大的差别。再比如,虽然算法 <code>B</code><code>C</code> 的时间复杂度要更高,但在输入数据大小 <span class="arithmatex">\(n\)</span> 比较小时,算法 <code>B</code> 是要明显优于算法 <code>C</code> 的。对于以上情况,我们很难仅凭时间复杂度来判定算法效率高低。然而,即使存在这些问题,复杂度分析仍然是评判算法效率的最有效且常用的方法。</p>
<h2 id="223">2.2.3. &nbsp; 函数渐近上界<a class="headerlink" href="#223" title="Permanent link">&para;</a></h2>
<p>设算法「计算操作数量」为 <span class="arithmatex">\(T(n)\)</span> ,其是一个关于输入数据大小 <span class="arithmatex">\(n\)</span> 的函数。例如,以下算法的操作数量为</p>
<div class="arithmatex">\[