This commit is contained in:
krahets
2023-07-31 03:27:06 +08:00
parent e0d4aed887
commit 3501592bbc
10 changed files with 627 additions and 257 deletions
+109 -6
View File
@@ -182,9 +182,40 @@ comments: true
=== "C"
```c title="subset_sum_i_naive.c"
[class]{}-[func]{backtrack}
/* 回溯算法:子集和 I */
void backtrack(vector *state, int target, int total, vector *choices, vector *res) {
// 子集和等于 target 时,记录解
if (total == target) {
vector *tmpVector = newVector();
for (int i = 0; i < state->size; i++) {
vectorPushback(tmpVector, state->data[i]);
}
vectorPushback(res, tmpVector);
return;
}
// 遍历所有选择
for (size_t i = 0; i < choices->size; i++) {
// 剪枝:若子集和超过 target ,则跳过该选择
if (total + *(int *)(choices->data[i]) > target) {
continue;
}
// 尝试:做出选择,更新元素和 total
vectorPushback(state, choices->data[i]);
// 进行下一轮选择
backtrack(state, target, total + *(int *)(choices->data[i]), choices, res);
// 回退:撤销选择,恢复到之前的状态
vectorPopback(state);
}
}
[class]{}-[func]{subsetSumINaive}
/* 求解子集和 I(包含重复子集) */
vector *subsetSumINaive(vector *nums, int target) {
vector *state = newVector(); // 状态(子集)
int total = 0; // 子集和
vector *res = newVector(); // 结果列表(子集列表)
backtrack(state, target, total, nums, res);
return res;
}
```
=== "C#"
@@ -518,9 +549,42 @@ comments: true
=== "C"
```c title="subset_sum_i.c"
[class]{}-[func]{backtrack}
/* 回溯算法:子集和 I */
void backtrack(vector *state, int target, vector *choices, int start, vector *res) {
// 子集和等于 target 时,记录解
if (target == 0) {
vector *tmpVector = newVector();
for (int i = 0; i < state->size; i++) {
vectorPushback(tmpVector, state->data[i]);
}
vectorPushback(res, tmpVector);
return;
}
// 遍历所有选择
// 剪枝二:从 start 开始遍历,避免生成重复子集
for (int i = start; i < choices->size; i++) {
// 剪枝:若子集和超过 target ,则跳过该选择
if (target - *(int *)(choices->data[i]) < 0) {
continue;
}
// 尝试:做出选择,更新 target, start
vectorPushback(state, choices->data[i]);
// 进行下一轮选择
backtrack(state, target - *(int *)(choices->data[i]), choices, i, res);
// 回退:撤销选择,恢复到之前的状态
vectorPopback(state);
}
}
[class]{}-[func]{subsetSumI}
/* 求解子集和 I */
vector *subsetSumI(vector *nums, int target) {
vector *state = newVector(); // 状态(子集)
qsort(nums->data[0], nums->size, sizeof(int), comp); // 对 nums 进行排序
int start = 0; // 子集和
vector *res = newVector(); // 结果列表(子集列表)
backtrack(state, target, nums, start, res);
return res;
}
```
=== "C#"
@@ -869,9 +933,48 @@ comments: true
=== "C"
```c title="subset_sum_ii.c"
[class]{}-[func]{backtrack}
/* 回溯算法:子集和 II */
void backtrack(vector *state, int target, vector *choices, int start, vector *res) {
// 子集和等于 target 时,记录解
if (target == 0) {
vector *tmpVector = newVector();
for (int i = 0; i < state->size; i++) {
vectorPushback(tmpVector, state->data[i]);
}
vectorPushback(res, tmpVector);
return;
}
// 遍历所有选择
// 剪枝二:从 start 开始遍历,避免生成重复子集
// 剪枝三:从 start 开始遍历,避免重复选择同一元素
for (int i = start; i < choices->size; i++) {
// 剪枝一:若子集和超过 target ,则直接结束循环
// 这是因为数组已排序,后边元素更大,子集和一定超过 target
if (target - *(int *)(choices->data[i]) < 0) {
continue;
}
// 剪枝四:如果该元素与左边元素相等,说明该搜索分支重复,直接跳过
if (i > start && *(int *)(choices->data[i]) == *(int *)(choices->data[i - 1])) {
continue;
}
// 尝试:做出选择,更新 target, start
vectorPushback(state, choices->data[i]);
// 进行下一轮选择
backtrack(state, target - *(int *)(choices->data[i]), choices, i + 1, res);
// 回退:撤销选择,恢复到之前的状态
vectorPopback(state);
}
}
[class]{}-[func]{subsetSumII}
/* 求解子集和 II */
vector *subsetSumII(vector *nums, int target) {
vector *state = newVector(); // 状态(子集)
qsort(nums->data[0], nums->size, sizeof(int), comp); // 对 nums 进行排序
int start = 0; // 子集和
vector *res = newVector(); // 结果列表(子集列表)
backtrack(state, target, nums, start, res);
return res;
}
```
=== "C#"