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https://github.com/krahets/hello-algo.git
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@@ -90,7 +90,7 @@ comments: true
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```python title="bubble_sort.py"
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def bubble_sort(nums: list[int]) -> None:
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""" 冒泡排序 """
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"""冒泡排序"""
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n: int = len(nums)
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# 外循环:待排序元素数量为 n-1, n-2, ..., 1
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for i in range(n - 1, 0, -1):
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@@ -294,7 +294,7 @@ comments: true
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```python title="bubble_sort.py"
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def bubble_sort_with_flag(nums: list[int]) -> None:
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""" 冒泡排序(标志优化) """
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"""冒泡排序(标志优化)"""
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n: int = len(nums)
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# 外循环:待排序元素数量为 n-1, n-2, ..., 1
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for i in range(n - 1, 0, -1):
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@@ -306,7 +306,7 @@ comments: true
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nums[j], nums[j + 1] = nums[j + 1], nums[j]
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flag = True # 记录交换元素
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if not flag:
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break # 此轮冒泡未交换任何元素,直接跳出
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break # 此轮冒泡未交换任何元素,直接跳出
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```
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=== "Go"
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@@ -87,6 +87,7 @@ comments: true
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```python title="bucket_sort.py"
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def bucket_sort(nums: list[float]) -> None:
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"""桶排序"""
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# 初始化 k = n/2 个桶,预期向每个桶分配 2 个元素
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k = len(nums) // 2
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buckets = [[] for _ in range(k)]
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@@ -76,7 +76,7 @@ comments: true
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```python title="counting_sort.py"
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def counting_sort_naive(nums: list[int]) -> None:
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""" 计数排序 """
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"""计数排序"""
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# 简单实现,无法用于排序对象
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# 1. 统计数组最大元素 m
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m = 0
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@@ -346,7 +346,7 @@ $$
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```python title="counting_sort.py"
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def counting_sort(nums: list[int]) -> None:
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""" 计数排序 """
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"""计数排序"""
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# 完整实现,可排序对象,并且是稳定排序
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# 1. 统计数组最大元素 m
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m = max(nums)
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@@ -66,8 +66,8 @@ comments: true
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```python title="insertion_sort.py"
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def insertion_sort(nums: list[int]) -> None:
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""" 插入排序 """
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# 外循环:base = nums[1], nums[2], ..., nums[n-1]
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"""插入排序"""
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# 外循环:base = nums[1], nums[2], ..., nums[n-1]
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for i in range(1, len(nums)):
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base: int = nums[i]
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j: int = i - 1
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@@ -75,7 +75,7 @@ comments: true
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while j >= 0 and nums[j] > base:
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nums[j + 1] = nums[j] # 1. 将 nums[j] 向右移动一位
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j -= 1
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nums[j + 1] = base # 2. 将 base 赋值到正确位置
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nums[j + 1] = base # 2. 将 base 赋值到正确位置
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```
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=== "Go"
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@@ -147,11 +147,11 @@ comments: true
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```python title="merge_sort.py"
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def merge(nums: list[int], left: int, mid: int, right: int) -> None:
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""" 合并左子数组和右子数组 """
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"""合并左子数组和右子数组"""
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# 左子数组区间 [left, mid]
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# 右子数组区间 [mid + 1, right]
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# 初始化辅助数组
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tmp: list[int] = list(nums[left:right + 1])
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tmp: list[int] = list(nums[left : right + 1])
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# 左子数组的起始索引和结束索引
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left_start: int = 0
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left_end: int = mid - left
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@@ -177,13 +177,13 @@ comments: true
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j += 1
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def merge_sort(nums: list[int], left: int, right: int) -> None:
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""" 归并排序 """
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"""归并排序"""
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# 终止条件
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if left >= right:
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return # 当子数组长度为 1 时终止递归
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return # 当子数组长度为 1 时终止递归
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# 划分阶段
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mid: int = (left + right) // 2 # 计算中点
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merge_sort(nums, left, mid) # 递归左子数组
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mid: int = (left + right) // 2 # 计算中点
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merge_sort(nums, left, mid) # 递归左子数组
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merge_sort(nums, mid + 1, right) # 递归右子数组
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# 合并阶段
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merge(nums, left, mid, right)
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@@ -101,7 +101,7 @@ comments: true
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```python title="quick_sort.py"
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def partition(self, nums: list[int], left: int, right: int) -> int:
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""" 哨兵划分 """
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"""哨兵划分"""
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# 以 nums[left] 作为基准数
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i, j = left, right
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while i < j:
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@@ -334,7 +334,7 @@ comments: true
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```python title="quick_sort.py"
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def quick_sort(self, nums: list[int], left: int, right: int) -> None:
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""" 快速排序 """
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"""快速排序"""
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# 子数组长度为 1 时终止递归
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if left >= right:
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return
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@@ -549,7 +549,7 @@ comments: true
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```python title="quick_sort.py"
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def median_three(self, nums: list[int], left: int, mid: int, right: int) -> int:
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""" 选取三个元素的中位数 """
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"""选取三个元素的中位数"""
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# 此处使用异或运算来简化代码
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# 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
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if (nums[left] < nums[mid]) ^ (nums[left] < nums[right]):
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@@ -559,7 +559,7 @@ comments: true
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return right
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def partition(self, nums: list[int], left: int, right: int) -> int:
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""" 哨兵划分(三数取中值) """
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"""哨兵划分(三数取中值)"""
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# 以 nums[left] 作为基准数
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med: int = self.median_three(nums, left, (left + right) // 2, right)
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# 将中位数交换至数组最左端
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@@ -842,7 +842,7 @@ comments: true
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```python title="quick_sort.py"
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def quick_sort(self, nums: list[int], left: int, right: int) -> None:
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""" 快速排序(尾递归优化) """
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"""快速排序(尾递归优化)"""
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# 子数组长度为 1 时终止
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while left < right:
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# 哨兵划分操作
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@@ -850,10 +850,10 @@ comments: true
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# 对两个子数组中较短的那个执行快排
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if pivot - left < right - pivot:
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self.quick_sort(nums, left, pivot - 1) # 递归排序左子数组
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left = pivot + 1 # 剩余待排序区间为 [pivot + 1, right]
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left = pivot + 1 # 剩余待排序区间为 [pivot + 1, right]
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else:
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self.quick_sort(nums, pivot + 1, right) # 递归排序右子数组
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right = pivot - 1 # 剩余待排序区间为 [left, pivot - 1]
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right = pivot - 1 # 剩余待排序区间为 [left, pivot - 1]
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```
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=== "Go"
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@@ -136,19 +136,19 @@ $$
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```python title="radix_sort.py"
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def digit(num: int, exp: int) -> int:
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""" 获取元素 num 的第 k 位,其中 exp = 10^(k-1) """
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"""获取元素 num 的第 k 位,其中 exp = 10^(k-1)"""
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# 传入 exp 而非 k 可以避免在此重复执行昂贵的次方计算
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return (num // exp) % 10
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def counting_sort_digit(nums: list[int], exp: int) -> None:
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""" 计数排序(根据 nums 第 k 位排序) """
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"""计数排序(根据 nums 第 k 位排序)"""
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# 十进制的位范围为 0~9 ,因此需要长度为 10 的桶
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counter = [0] * 10
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n = len(nums)
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# 统计 0~9 各数字的出现次数
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for i in range(n):
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d = digit(nums[i], exp) # 获取 nums[i] 第 k 位,记为 d
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counter[d] += 1 # 统计数字 d 的出现次数
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counter[d] += 1 # 统计数字 d 的出现次数
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# 求前缀和,将“出现个数”转换为“数组索引”
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for i in range(1, 10):
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counter[i] += counter[i - 1]
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@@ -157,14 +157,14 @@ $$
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for i in range(n - 1, -1, -1):
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d = digit(nums[i], exp)
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j = counter[d] - 1 # 获取 d 在数组中的索引 j
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res[j] = nums[i] # 将当前元素填入索引 j
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counter[d] -= 1 # 将 d 的数量减 1
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res[j] = nums[i] # 将当前元素填入索引 j
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counter[d] -= 1 # 将 d 的数量减 1
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# 使用结果覆盖原数组 nums
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for i in range(n):
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nums[i] = res[i]
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def radix_sort(nums: list[int]) -> None:
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""" 基数排序 """
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"""基数排序"""
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# 获取数组的最大元素,用于判断最大位数
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m = max(nums)
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# 按照从低位到高位的顺序遍历
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