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@@ -355,7 +355,7 @@ comments: true
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```rust title="subset_sum_i_naive.rs"
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/* 回溯算法:子集和 I */
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fn backtrack(
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mut state: Vec<i32>,
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state: &mut Vec<i32>,
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target: i32,
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total: i32,
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choices: &[i32],
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@@ -363,7 +363,7 @@ comments: true
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) {
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// 子集和等于 target 时,记录解
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if total == target {
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res.push(state);
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res.push(state.clone());
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return;
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}
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// 遍历所有选择
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@@ -375,7 +375,7 @@ comments: true
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// 尝试:做出选择,更新元素和 total
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state.push(choices[i]);
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// 进行下一轮选择
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backtrack(state.clone(), target, total + choices[i], choices, res);
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backtrack(state, target, total + choices[i], choices, res);
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// 回退:撤销选择,恢复到之前的状态
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state.pop();
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}
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@@ -383,10 +383,10 @@ comments: true
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/* 求解子集和 I(包含重复子集) */
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fn subset_sum_i_naive(nums: &[i32], target: i32) -> Vec<Vec<i32>> {
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let state = Vec::new(); // 状态(子集)
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let mut state = Vec::new(); // 状态(子集)
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let total = 0; // 子集和
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let mut res = Vec::new(); // 结果列表(子集列表)
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backtrack(state, target, total, nums, &mut res);
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backtrack(&mut state, target, total, nums, &mut res);
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res
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}
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```
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@@ -912,7 +912,7 @@ comments: true
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```rust title="subset_sum_i.rs"
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/* 回溯算法:子集和 I */
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fn backtrack(
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mut state: Vec<i32>,
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state: &mut Vec<i32>,
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target: i32,
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choices: &[i32],
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start: usize,
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@@ -920,7 +920,7 @@ comments: true
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) {
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// 子集和等于 target 时,记录解
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if target == 0 {
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res.push(state);
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res.push(state.clone());
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return;
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}
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// 遍历所有选择
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@@ -934,7 +934,7 @@ comments: true
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// 尝试:做出选择,更新 target, start
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state.push(choices[i]);
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// 进行下一轮选择
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backtrack(state.clone(), target - choices[i], choices, i, res);
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backtrack(state, target - choices[i], choices, i, res);
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// 回退:撤销选择,恢复到之前的状态
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state.pop();
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}
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@@ -942,11 +942,11 @@ comments: true
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/* 求解子集和 I */
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fn subset_sum_i(nums: &mut [i32], target: i32) -> Vec<Vec<i32>> {
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let state = Vec::new(); // 状态(子集)
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let mut state = Vec::new(); // 状态(子集)
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nums.sort(); // 对 nums 进行排序
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let start = 0; // 遍历起始点
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let mut res = Vec::new(); // 结果列表(子集列表)
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backtrack(state, target, nums, start, &mut res);
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backtrack(&mut state, target, nums, start, &mut res);
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res
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}
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```
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@@ -1512,7 +1512,7 @@ comments: true
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```rust title="subset_sum_ii.rs"
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/* 回溯算法:子集和 II */
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fn backtrack(
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mut state: Vec<i32>,
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state: &mut Vec<i32>,
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target: i32,
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choices: &[i32],
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start: usize,
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@@ -1520,7 +1520,7 @@ comments: true
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) {
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// 子集和等于 target 时,记录解
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if target == 0 {
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res.push(state);
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res.push(state.clone());
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return;
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}
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// 遍历所有选择
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@@ -1539,7 +1539,7 @@ comments: true
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// 尝试:做出选择,更新 target, start
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state.push(choices[i]);
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// 进行下一轮选择
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backtrack(state.clone(), target - choices[i], choices, i, res);
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backtrack(state, target - choices[i], choices, i + 1, res);
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// 回退:撤销选择,恢复到之前的状态
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state.pop();
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}
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@@ -1547,11 +1547,11 @@ comments: true
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/* 求解子集和 II */
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fn subset_sum_ii(nums: &mut [i32], target: i32) -> Vec<Vec<i32>> {
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let state = Vec::new(); // 状态(子集)
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let mut state = Vec::new(); // 状态(子集)
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nums.sort(); // 对 nums 进行排序
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let start = 0; // 遍历起始点
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let mut res = Vec::new(); // 结果列表(子集列表)
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backtrack(state, target, nums, start, &mut res);
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backtrack(&mut state, target, nums, start, &mut res);
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res
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}
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```
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