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krahets
2023-05-26 04:47:54 +08:00
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chapter_searching/replace_linear_by_hashing.md
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@@ -200,7 +200,7 @@ comments: true
考虑借助一个哈希表，键值对分别为数组元素和元素索引。循环遍历数组，每轮执行：
1. 判断数字 `target - nums[i]` 是否在哈希表中，若是则直接返回这两个元素的索引；
2. 将键值对 `num[i]` 和索引 `i` 添加进哈希表；
2. 将键值对 `nums[i]` 和索引 `i` 添加进哈希表；
=== "<1>"
![辅助哈希表求解两数之和](replace_linear_by_hashing.assets/two_sum_hashtable_step1.png)