mirror of
https://github.com/krahets/hello-algo.git
synced 2026-08-15 05:00:59 +00:00
Sync zh and zh-hant versions. (#1523)
This commit is contained in:
@@ -16,11 +16,7 @@ fn backtrack(
|
||||
) {
|
||||
// 當放置完所有行時,記錄解
|
||||
if row == n {
|
||||
let mut copy_state: Vec<Vec<String>> = Vec::new();
|
||||
for s_row in state.clone() {
|
||||
copy_state.push(s_row);
|
||||
}
|
||||
res.push(copy_state);
|
||||
res.push(state.clone());
|
||||
return;
|
||||
}
|
||||
// 走訪所有列
|
||||
@@ -31,12 +27,12 @@ fn backtrack(
|
||||
// 剪枝:不允許該格子所在列、主對角線、次對角線上存在皇后
|
||||
if !cols[col] && !diags1[diag1] && !diags2[diag2] {
|
||||
// 嘗試:將皇后放置在該格子
|
||||
state.get_mut(row).unwrap()[col] = "Q".into();
|
||||
state[row][col] = "Q".into();
|
||||
(cols[col], diags1[diag1], diags2[diag2]) = (true, true, true);
|
||||
// 放置下一行
|
||||
backtrack(row + 1, n, state, res, cols, diags1, diags2);
|
||||
// 回退:將該格子恢復為空位
|
||||
state.get_mut(row).unwrap()[col] = "#".into();
|
||||
state[row][col] = "#".into();
|
||||
(cols[col], diags1[diag1], diags2[diag2]) = (false, false, false);
|
||||
}
|
||||
}
|
||||
@@ -45,14 +41,7 @@ fn backtrack(
|
||||
/* 求解 n 皇后 */
|
||||
fn n_queens(n: usize) -> Vec<Vec<Vec<String>>> {
|
||||
// 初始化 n*n 大小的棋盤,其中 'Q' 代表皇后,'#' 代表空位
|
||||
let mut state: Vec<Vec<String>> = Vec::new();
|
||||
for _ in 0..n {
|
||||
let mut row: Vec<String> = Vec::new();
|
||||
for _ in 0..n {
|
||||
row.push("#".into());
|
||||
}
|
||||
state.push(row);
|
||||
}
|
||||
let mut state: Vec<Vec<String>> = vec![vec!["#".to_string(); n]; n];
|
||||
let mut cols = vec![false; n]; // 記錄列是否有皇后
|
||||
let mut diags1 = vec![false; 2 * n - 1]; // 記錄主對角線上是否有皇后
|
||||
let mut diags2 = vec![false; 2 * n - 1]; // 記錄次對角線上是否有皇后
|
||||
|
||||
@@ -6,7 +6,7 @@
|
||||
|
||||
/* 回溯演算法:子集和 I */
|
||||
fn backtrack(
|
||||
mut state: Vec<i32>,
|
||||
state: &mut Vec<i32>,
|
||||
target: i32,
|
||||
choices: &[i32],
|
||||
start: usize,
|
||||
@@ -14,7 +14,7 @@ fn backtrack(
|
||||
) {
|
||||
// 子集和等於 target 時,記錄解
|
||||
if target == 0 {
|
||||
res.push(state);
|
||||
res.push(state.clone());
|
||||
return;
|
||||
}
|
||||
// 走訪所有選擇
|
||||
@@ -28,7 +28,7 @@ fn backtrack(
|
||||
// 嘗試:做出選擇,更新 target, start
|
||||
state.push(choices[i]);
|
||||
// 進行下一輪選擇
|
||||
backtrack(state.clone(), target - choices[i], choices, i, res);
|
||||
backtrack(state, target - choices[i], choices, i, res);
|
||||
// 回退:撤銷選擇,恢復到之前的狀態
|
||||
state.pop();
|
||||
}
|
||||
@@ -36,11 +36,11 @@ fn backtrack(
|
||||
|
||||
/* 求解子集和 I */
|
||||
fn subset_sum_i(nums: &mut [i32], target: i32) -> Vec<Vec<i32>> {
|
||||
let state = Vec::new(); // 狀態(子集)
|
||||
let mut state = Vec::new(); // 狀態(子集)
|
||||
nums.sort(); // 對 nums 進行排序
|
||||
let start = 0; // 走訪起始點
|
||||
let mut res = Vec::new(); // 結果串列(子集串列)
|
||||
backtrack(state, target, nums, start, &mut res);
|
||||
backtrack(&mut state, target, nums, start, &mut res);
|
||||
res
|
||||
}
|
||||
|
||||
|
||||
@@ -6,7 +6,7 @@
|
||||
|
||||
/* 回溯演算法:子集和 I */
|
||||
fn backtrack(
|
||||
mut state: Vec<i32>,
|
||||
state: &mut Vec<i32>,
|
||||
target: i32,
|
||||
total: i32,
|
||||
choices: &[i32],
|
||||
@@ -14,7 +14,7 @@ fn backtrack(
|
||||
) {
|
||||
// 子集和等於 target 時,記錄解
|
||||
if total == target {
|
||||
res.push(state);
|
||||
res.push(state.clone());
|
||||
return;
|
||||
}
|
||||
// 走訪所有選擇
|
||||
@@ -26,7 +26,7 @@ fn backtrack(
|
||||
// 嘗試:做出選擇,更新元素和 total
|
||||
state.push(choices[i]);
|
||||
// 進行下一輪選擇
|
||||
backtrack(state.clone(), target, total + choices[i], choices, res);
|
||||
backtrack(state, target, total + choices[i], choices, res);
|
||||
// 回退:撤銷選擇,恢復到之前的狀態
|
||||
state.pop();
|
||||
}
|
||||
@@ -34,10 +34,10 @@ fn backtrack(
|
||||
|
||||
/* 求解子集和 I(包含重複子集) */
|
||||
fn subset_sum_i_naive(nums: &[i32], target: i32) -> Vec<Vec<i32>> {
|
||||
let state = Vec::new(); // 狀態(子集)
|
||||
let mut state = Vec::new(); // 狀態(子集)
|
||||
let total = 0; // 子集和
|
||||
let mut res = Vec::new(); // 結果串列(子集串列)
|
||||
backtrack(state, target, total, nums, &mut res);
|
||||
backtrack(&mut state, target, total, nums, &mut res);
|
||||
res
|
||||
}
|
||||
|
||||
|
||||
@@ -6,7 +6,7 @@
|
||||
|
||||
/* 回溯演算法:子集和 II */
|
||||
fn backtrack(
|
||||
mut state: Vec<i32>,
|
||||
state: &mut Vec<i32>,
|
||||
target: i32,
|
||||
choices: &[i32],
|
||||
start: usize,
|
||||
@@ -14,7 +14,7 @@ fn backtrack(
|
||||
) {
|
||||
// 子集和等於 target 時,記錄解
|
||||
if target == 0 {
|
||||
res.push(state);
|
||||
res.push(state.clone());
|
||||
return;
|
||||
}
|
||||
// 走訪所有選擇
|
||||
@@ -33,7 +33,7 @@ fn backtrack(
|
||||
// 嘗試:做出選擇,更新 target, start
|
||||
state.push(choices[i]);
|
||||
// 進行下一輪選擇
|
||||
backtrack(state.clone(), target - choices[i], choices, i + 1, res);
|
||||
backtrack(state, target - choices[i], choices, i + 1, res);
|
||||
// 回退:撤銷選擇,恢復到之前的狀態
|
||||
state.pop();
|
||||
}
|
||||
@@ -41,11 +41,11 @@ fn backtrack(
|
||||
|
||||
/* 求解子集和 II */
|
||||
fn subset_sum_ii(nums: &mut [i32], target: i32) -> Vec<Vec<i32>> {
|
||||
let state = Vec::new(); // 狀態(子集)
|
||||
let mut state = Vec::new(); // 狀態(子集)
|
||||
nums.sort(); // 對 nums 進行排序
|
||||
let start = 0; // 走訪起始點
|
||||
let mut res = Vec::new(); // 結果串列(子集串列)
|
||||
backtrack(state, target, nums, start, &mut res);
|
||||
backtrack(&mut state, target, nums, start, &mut res);
|
||||
res
|
||||
}
|
||||
|
||||
|
||||
Reference in New Issue
Block a user