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Add JavaScript and TypeScript code of top_k and update some code style (#686)
* Update JS and TS code style * Add JavaScript and TypeScript code of top_k * Update top_k.ts * Apply suggestions from code review Co-authored-by: Justin Tse <xiefahit@gmail.com> * Apply suggestions from code review Co-authored-by: Justin Tse <xiefahit@gmail.com> --------- Co-authored-by: Yudong Jin <krahets@163.com>
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@@ -53,7 +53,7 @@ function traverse(nums: number[]): void {
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count++;
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}
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// 直接遍历数组
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for (let num of nums) {
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for (const num of nums) {
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count += 1;
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}
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}
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@@ -98,4 +98,4 @@ traverse(nums);
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let index = find(nums, 3);
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console.log('在 nums 中查找元素 3 ,得到索引 =', index);
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export {};
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export { };
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@@ -14,7 +14,7 @@ function backtrack(
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// 当爬到第 n 阶时,方案数量加 1
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if (state === n) res.set(0, res.get(0) + 1);
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// 遍历所有选择
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for (let choice of choices) {
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for (const choice of choices) {
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// 剪枝:不允许越过第 n 阶
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if (state + choice > n) break;
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// 尝试:做出选择,更新状态
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@@ -38,4 +38,4 @@ const n = 9;
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const res = climbingStairsBacktrack(n);
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console.log(`爬 ${n} 阶楼梯共有 ${res} 种方案`);
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export {};
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export { };
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@@ -70,7 +70,7 @@ class GraphAdjList {
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// 在邻接表中删除顶点 vet 对应的链表
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this.adjList.delete(vet);
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// 遍历其他顶点的链表,删除所有包含 vet 的边
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for (let set of this.adjList.values()) {
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for (const set of this.adjList.values()) {
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const index: number = set.indexOf(vet);
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if (index > -1) {
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set.splice(index, 1);
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@@ -114,6 +114,11 @@ class MaxHeap {
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public print(): void {
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printHeap(this.maxHeap);
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}
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/* 取出堆中元素 */
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public getMaxHeap(): number[] {
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return this.maxHeap;
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}
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}
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/* Driver Code */
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@@ -144,3 +149,5 @@ console.log(`\n堆元素数量为 ${size}`);
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/* 判断堆是否为空 */
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const isEmpty = maxHeap.isEmpty();
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console.log(`\n堆是否为空 ${isEmpty}`);
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export { MaxHeap };
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@@ -0,0 +1,34 @@
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/**
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* File: top_k.ts
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* Created Time: 2023-08-13
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* Author: Justin (xiefahit@gmail.com)
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*/
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import { MaxHeap } from './my_heap';
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/* 基于堆查找数组中最大的 k 个元素 */
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function top_k_heap(nums: number[], k: number): number[] {
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// 将堆中所有元素取反,从而用大顶堆来模拟小顶堆
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const invertedNums = nums.map(num => -num);
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// 将数组的前 k 个元素入堆
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const heap = new MaxHeap(invertedNums.slice(0, k));
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// 从第 k+1 个元素开始,保持堆的长度为 k
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for (let i = k; i < invertedNums.length; i++) {
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// 若当前元素小于堆顶元素,则将堆顶元素出堆、当前元素入堆
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if (invertedNums[i] < heap.peek()) {
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heap.pop();
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heap.push(invertedNums[i]);
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}
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}
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// 取出堆中元素
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const maxHeap = heap.getMaxHeap();
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// 对堆中元素取相反数
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const invertedMaxHeap = maxHeap.map(num => -num);
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return invertedMaxHeap;
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}
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/* Driver Code */
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const nums = [1, 7, 6, 3, 2];
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const k = 3;
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const res = top_k_heap(nums, k);
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console.log(`最大的 ${k} 个元素为`, res);
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