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https://github.com/krahets/hello-algo.git
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feat: Traditional Chinese version (#1163)
* First commit * Update mkdocs.yml * Translate all the docs to traditional Chinese * Translate the code files. * Translate the docker file * Fix mkdocs.yml * Translate all the figures from SC to TC * 二叉搜尋樹 -> 二元搜尋樹 * Update terminology. * Update terminology * 构造函数/构造方法 -> 建構子 异或 -> 互斥或 * 擴充套件 -> 擴展 * constant - 常量 - 常數 * 類 -> 類別 * AVL -> AVL 樹 * 數組 -> 陣列 * 係統 -> 系統 斐波那契數列 -> 費波那契數列 運算元量 -> 運算量 引數 -> 參數 * 聯絡 -> 關聯 * 麵試 -> 面試 * 面向物件 -> 物件導向 歸併排序 -> 合併排序 范式 -> 範式 * Fix 算法 -> 演算法 * 錶示 -> 表示 反碼 -> 一補數 補碼 -> 二補數 列列尾部 -> 佇列尾部 區域性性 -> 區域性 一摞 -> 一疊 * Synchronize with main branch * 賬號 -> 帳號 推匯 -> 推導 * Sync with main branch * First commit * Update mkdocs.yml * Translate all the docs to traditional Chinese * Translate the code files. * Translate the docker file * Fix mkdocs.yml * Translate all the figures from SC to TC * 二叉搜尋樹 -> 二元搜尋樹 * Update terminology * 构造函数/构造方法 -> 建構子 异或 -> 互斥或 * 擴充套件 -> 擴展 * constant - 常量 - 常數 * 類 -> 類別 * AVL -> AVL 樹 * 數組 -> 陣列 * 係統 -> 系統 斐波那契數列 -> 費波那契數列 運算元量 -> 運算量 引數 -> 參數 * 聯絡 -> 關聯 * 麵試 -> 面試 * 面向物件 -> 物件導向 歸併排序 -> 合併排序 范式 -> 範式 * Fix 算法 -> 演算法 * 錶示 -> 表示 反碼 -> 一補數 補碼 -> 二補數 列列尾部 -> 佇列尾部 區域性性 -> 區域性 一摞 -> 一疊 * Synchronize with main branch * 賬號 -> 帳號 推匯 -> 推導 * Sync with main branch * Update terminology.md * 操作数量(num. of operations)-> 操作數量 * 字首和->前綴和 * Update figures * 歸 -> 迴 記憶體洩漏 -> 記憶體流失 * Fix the bug of the file filter * 支援 -> 支持 Add zh-Hant/README.md * Add the zh-Hant chapter covers. Bug fixes. * 外掛 -> 擴充功能 * Add the landing page for zh-Hant version * Unify the font of the chapter covers for the zh, en, and zh-Hant version * Move zh-Hant/ to zh-hant/ * Translate terminology.md to traditional Chinese
This commit is contained in:
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"""
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File: binary_search_recur.py
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Created Time: 2023-07-17
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Author: krahets (krahets@163.com)
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"""
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def dfs(nums: list[int], target: int, i: int, j: int) -> int:
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"""二分搜尋:問題 f(i, j)"""
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# 若區間為空,代表無目標元素,則返回 -1
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if i > j:
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return -1
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# 計算中點索引 m
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m = (i + j) // 2
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if nums[m] < target:
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# 遞迴子問題 f(m+1, j)
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return dfs(nums, target, m + 1, j)
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elif nums[m] > target:
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# 遞迴子問題 f(i, m-1)
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return dfs(nums, target, i, m - 1)
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else:
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# 找到目標元素,返回其索引
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return m
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def binary_search(nums: list[int], target: int) -> int:
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"""二分搜尋"""
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n = len(nums)
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# 求解問題 f(0, n-1)
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return dfs(nums, target, 0, n - 1)
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"""Driver Code"""
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if __name__ == "__main__":
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target = 6
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nums = [1, 3, 6, 8, 12, 15, 23, 26, 31, 35]
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# 二分搜尋(雙閉區間)
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index = binary_search(nums, target)
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print("目標元素 6 的索引 = ", index)
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@@ -0,0 +1,54 @@
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"""
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File: build_tree.py
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Created Time: 2023-07-15
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Author: krahets (krahets@163.com)
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"""
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import sys
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from pathlib import Path
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sys.path.append(str(Path(__file__).parent.parent))
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from modules import TreeNode, print_tree
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def dfs(
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preorder: list[int],
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inorder_map: dict[int, int],
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i: int,
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l: int,
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r: int,
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) -> TreeNode | None:
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"""構建二元樹:分治"""
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# 子樹區間為空時終止
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if r - l < 0:
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return None
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# 初始化根節點
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root = TreeNode(preorder[i])
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# 查詢 m ,從而劃分左右子樹
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m = inorder_map[preorder[i]]
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# 子問題:構建左子樹
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root.left = dfs(preorder, inorder_map, i + 1, l, m - 1)
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# 子問題:構建右子樹
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root.right = dfs(preorder, inorder_map, i + 1 + m - l, m + 1, r)
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# 返回根節點
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return root
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def build_tree(preorder: list[int], inorder: list[int]) -> TreeNode | None:
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"""構建二元樹"""
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# 初始化雜湊表,儲存 inorder 元素到索引的對映
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inorder_map = {val: i for i, val in enumerate(inorder)}
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root = dfs(preorder, inorder_map, 0, 0, len(inorder) - 1)
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return root
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"""Driver Code"""
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if __name__ == "__main__":
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preorder = [3, 9, 2, 1, 7]
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inorder = [9, 3, 1, 2, 7]
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print(f"前序走訪 = {preorder}")
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print(f"中序走訪 = {inorder}")
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root = build_tree(preorder, inorder)
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print("構建的二元樹為:")
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print_tree(root)
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"""
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File: hanota.py
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Created Time: 2023-07-16
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Author: krahets (krahets@163.com)
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"""
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def move(src: list[int], tar: list[int]):
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"""移動一個圓盤"""
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# 從 src 頂部拿出一個圓盤
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pan = src.pop()
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# 將圓盤放入 tar 頂部
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tar.append(pan)
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def dfs(i: int, src: list[int], buf: list[int], tar: list[int]):
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"""求解河內塔問題 f(i)"""
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# 若 src 只剩下一個圓盤,則直接將其移到 tar
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if i == 1:
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move(src, tar)
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return
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# 子問題 f(i-1) :將 src 頂部 i-1 個圓盤藉助 tar 移到 buf
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dfs(i - 1, src, tar, buf)
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# 子問題 f(1) :將 src 剩餘一個圓盤移到 tar
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move(src, tar)
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# 子問題 f(i-1) :將 buf 頂部 i-1 個圓盤藉助 src 移到 tar
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dfs(i - 1, buf, src, tar)
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def solve_hanota(A: list[int], B: list[int], C: list[int]):
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"""求解河內塔問題"""
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n = len(A)
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# 將 A 頂部 n 個圓盤藉助 B 移到 C
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dfs(n, A, B, C)
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"""Driver Code"""
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if __name__ == "__main__":
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# 串列尾部是柱子頂部
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A = [5, 4, 3, 2, 1]
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B = []
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C = []
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print("初始狀態下:")
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print(f"A = {A}")
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print(f"B = {B}")
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print(f"C = {C}")
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solve_hanota(A, B, C)
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print("圓盤移動完成後:")
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print(f"A = {A}")
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print(f"B = {B}")
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print(f"C = {C}")
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