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@@ -506,9 +506,36 @@ comments: true
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=== "Ruby"
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```ruby title="permutations_i.rb"
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[class]{}-[func]{backtrack}
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### 回溯演算法:全排列 I ###
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def backtrack(state, choices, selected, res)
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# 當狀態長度等於元素數量時,記錄解
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if state.length == choices.length
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res << state.dup
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return
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end
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[class]{}-[func]{permutations_i}
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# 走訪所有選擇
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choices.each_with_index do |choice, i|
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# 剪枝:不允許重複選擇元素
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unless selected[i]
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# 嘗試:做出選擇,更新狀態
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selected[i] = true
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state << choice
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# 進行下一輪選擇
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backtrack(state, choices, selected, res)
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# 回退:撤銷選擇,恢復到之前的狀態
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selected[i] = false
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state.pop
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end
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end
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end
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### 全排列 I ###
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def permutations_i(nums)
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res = []
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backtrack([], nums, Array.new(nums.length, false), res)
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res
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end
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```
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=== "Zig"
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@@ -1032,9 +1059,38 @@ comments: true
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=== "Ruby"
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```ruby title="permutations_ii.rb"
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[class]{}-[func]{backtrack}
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### 回溯演算法:全排列 II ###
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def backtrack(state, choices, selected, res)
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# 當狀態長度等於元素數量時,記錄解
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if state.length == choices.length
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res << state.dup
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return
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end
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[class]{}-[func]{permutations_ii}
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# 走訪所有選擇
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duplicated = Set.new
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choices.each_with_index do |choice, i|
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# 剪枝:不允許重複選擇元素 且 不允許重複選擇相等元素
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if !selected[i] && !duplicated.include?(choice)
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# 嘗試:做出選擇,更新狀態
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duplicated.add(choice)
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selected[i] = true
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state << choice
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# 進行下一輪選擇
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backtrack(state, choices, selected, res)
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# 回退:撤銷選擇,恢復到之前的狀態
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selected[i] = false
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state.pop
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end
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end
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end
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### 全排列 II ###
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def permutations_ii(nums)
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res = []
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backtrack([], nums, Array.new(nums.length, false), res)
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res
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end
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```
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=== "Zig"
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