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2023-09-22 13:08:10 +08:00
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10.2 &nbsp; 二分查找插入点
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10.3 &nbsp; 二分查找边界
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第 12 章 &nbsp; 分治
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12.1 &nbsp; 分治算法
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12.2 &nbsp; 分治搜索策略
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12.3 &nbsp; 构建树问题
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12.4 &nbsp; 汉诺塔问题
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12.5 &nbsp; 小结
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第 14 章 &nbsp; 动态规划
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14.1 &nbsp; 初探动态规划
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14.2 &nbsp; DP 问题特性
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14.3 &nbsp; DP 解题思路
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14.4 &nbsp; 0-1 背包问题
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14.5 &nbsp; 完全背包问题
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14.6 &nbsp; 编辑距离问题
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14.7 &nbsp; 小结
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第 15 章 &nbsp; 贪心
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15.1 &nbsp; 贪心算法
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15.2 &nbsp; 分数背包问题
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15.3 &nbsp; 最大容量问题
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15.4 &nbsp; 最大切分乘积问题
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15.5 &nbsp; 小结
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</div>
<h2 id="1041">10.4.1 &nbsp; 线性查找：以时间换空间<a class="headerlink" href="#1041" title="Permanent link">&para;</a></h2>
<p>考虑直接遍历所有可能的组合。如图 10-9 所示，我们开启一个两层循环，在每轮中判断两个整数的和是否为 <code>target</code> ，若是则返回它们的索引。</p>
<p><img alt="线性查找求解两数之和" src="../replace_linear_by_hashing.assets/two_sum_brute_force.png" /></p>
<p><a class="glightbox" href="../replace_linear_by_hashing.assets/two_sum_brute_force.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="线性查找求解两数之和" src="../replace_linear_by_hashing.assets/two_sum_brute_force.png" /></a></p>
<p align="center"> 图 10-9 &nbsp; 线性查找求解两数之和 </p>
<div class="tabbed-set tabbed-alternate" data-tabs="1:12"><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><input id="__tabbed_1_2" name="__tabbed_1" type="radio" /><input id="__tabbed_1_3" name="__tabbed_1" type="radio" /><input id="__tabbed_1_4" name="__tabbed_1" type="radio" /><input id="__tabbed_1_5" name="__tabbed_1" type="radio" /><input id="__tabbed_1_6" name="__tabbed_1" type="radio" /><input id="__tabbed_1_7" name="__tabbed_1" type="radio" /><input id="__tabbed_1_8" name="__tabbed_1" type="radio" /><input id="__tabbed_1_9" name="__tabbed_1" type="radio" /><input id="__tabbed_1_10" name="__tabbed_1" type="radio" /><input id="__tabbed_1_11" name="__tabbed_1" type="radio" /><input id="__tabbed_1_12" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">Python</label><label for="__tabbed_1_2">C++</label><label for="__tabbed_1_3">Java</label><label for="__tabbed_1_4">C#</label><label for="__tabbed_1_5">Go</label><label for="__tabbed_1_6">Swift</label><label for="__tabbed_1_7">JS</label><label for="__tabbed_1_8">TS</label><label for="__tabbed_1_9">Dart</label><label for="__tabbed_1_10">Rust</label><label for="__tabbed_1_11">C</label><label for="__tabbed_1_12">Zig</label></div>
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<div class="tabbed-set tabbed-alternate" data-tabs="2:3"><input checked="checked" id="__tabbed_2_1" name="__tabbed_2" type="radio" /><input id="__tabbed_2_2" name="__tabbed_2" type="radio" /><input id="__tabbed_2_3" name="__tabbed_2" type="radio" /><div class="tabbed-labels"><label for="__tabbed_2_1">&lt;1&gt;</label><label for="__tabbed_2_2">&lt;2&gt;</label><label for="__tabbed_2_3">&lt;3&gt;</label></div>
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<p><img alt="辅助哈希表求解两数之和" src="../replace_linear_by_hashing.assets/two_sum_hashtable_step1.png" /></p>
<p><a class="glightbox" href="../replace_linear_by_hashing.assets/two_sum_hashtable_step1.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="辅助哈希表求解两数之和" src="../replace_linear_by_hashing.assets/two_sum_hashtable_step1.png" /></a></p>
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<p><img alt="two_sum_hashtable_step2" src="../replace_linear_by_hashing.assets/two_sum_hashtable_step2.png" /></p>
<p><a class="glightbox" href="../replace_linear_by_hashing.assets/two_sum_hashtable_step2.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="two_sum_hashtable_step2" src="../replace_linear_by_hashing.assets/two_sum_hashtable_step2.png" /></a></p>
</div>
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<p><img alt="two_sum_hashtable_step3" src="../replace_linear_by_hashing.assets/two_sum_hashtable_step3.png" /></p>
<p><a class="glightbox" href="../replace_linear_by_hashing.assets/two_sum_hashtable_step3.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="two_sum_hashtable_step3" src="../replace_linear_by_hashing.assets/two_sum_hashtable_step3.png" /></a></p>
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