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krahets
2024-09-28 09:26:59 +08:00
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chapter_greedy/max_capacity_problem/index.html
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@@ -3708,7 +3708,7 @@ cap[i, j] = \min(ht[i], ht[j]) \times (j - i)
<ol>
<li>初始状态下，指针 <span class="arithmatex">\(i\)</span> 和 <span class="arithmatex">\(j\)</span> 分列数组两端。</li>
<li>计算当前状态的容量 <span class="arithmatex">\(cap[i, j]\)</span> ，并更新最大容量。</li>
<li>比较板 <span class="arithmatex">\(i\)</span> 和 板 <span class="arithmatex">\(j\)</span> 的高度，并将短板向内移动一格。</li>
<li>比较板 <span class="arithmatex">\(i\)</span> 和板 <span class="arithmatex">\(j\)</span> 的高度，并将短板向内移动一格。</li>
<li>循环执行第 <code>2.</code> 步和第 <code>3.</code> 步，直至 <span class="arithmatex">\(i\)</span> 和 <span class="arithmatex">\(j\)</span> 相遇时结束。</li>
</ol>
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