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完善所以c#相关的文档和代码
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@@ -344,7 +344,48 @@ comments: true
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=== "C#"
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```csharp title="merge_sort.cs"
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/**
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* 合并左子数组和右子数组
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* 左子数组区间 [left, mid]
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* 右子数组区间 [mid + 1, right]
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*/
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void merge(int[] nums, int left, int mid, int right)
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{
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// 初始化辅助数组
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int[] tmp = nums[left..(right + 1)];//Array.CopyOfRange(nums, left, right + 1);
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// 左子数组的起始索引和结束索引
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int leftStart = left - left, leftEnd = mid - left;
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// 右子数组的起始索引和结束索引
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int rightStart = mid + 1 - left, rightEnd = right - left;
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// i, j 分别指向左子数组、右子数组的首元素
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int i = leftStart, j = rightStart;
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// 通过覆盖原数组 nums 来合并左子数组和右子数组
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for (int k = left; k <= right; k++)
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{
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// 若“左子数组已全部合并完”,则选取右子数组元素,并且 j++
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if (i > leftEnd)
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nums[k] = tmp[j++];
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// 否则,若“右子数组已全部合并完”或“左子数组元素 < 右子数组元素”,则选取左子数组元素,并且 i++
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else if (j > rightEnd || tmp[i] <= tmp[j])
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nums[k] = tmp[i++];
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// 否则,若“左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++
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else
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nums[k] = tmp[j++];
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}
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}
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/* 归并排序 */
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void mergeSort(int[] nums, int left, int right)
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{
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// 终止条件
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if (left >= right) return; // 当子数组长度为 1 时终止递归
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// 划分阶段
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int mid = (left + right) / 2; // 计算中点
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mergeSort(nums, left, mid); // 递归左子数组
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mergeSort(nums, mid + 1, right); // 递归右子数组
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// 合并阶段
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merge(nums, left, mid, right);
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}
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```
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下面重点解释一下合并方法 `merge()` 的流程:
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