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@@ -139,22 +139,20 @@ comments: true
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=== "C#"
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```csharp title="leetcode_two_sum.cs"
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class SolutionBruteForce
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/* 方法一:暴力枚举 */
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int[] twoSumBruteForce(int[] nums, int target)
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{
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public int[] twoSum(int[] nums, int target)
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int size = nums.Length;
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// 两层循环,时间复杂度 O(n^2)
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for (int i = 0; i < size - 1; i++)
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{
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int size = nums.Length;
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// 两层循环,时间复杂度 O(n^2)
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for (int i = 0; i < size - 1; i++)
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for (int j = i + 1; j < size; j++)
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{
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for (int j = i + 1; j < size; j++)
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{
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if (nums[i] + nums[j] == target)
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return new int[] { i, j };
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}
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if (nums[i] + nums[j] == target)
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return new int[] { i, j };
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}
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return new int[0];
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}
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return new int[0];
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}
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```
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@@ -321,24 +319,22 @@ comments: true
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=== "C#"
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```csharp title="leetcode_two_sum.cs"
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class SolutionHashMap
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/* 方法二:辅助哈希表 */
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int[] twoSumHashTable(int[] nums, int target)
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{
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public int[] twoSum(int[] nums, int target)
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int size = nums.Length;
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// 辅助哈希表,空间复杂度 O(n)
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Dictionary<int, int> dic = new();
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// 单层循环,时间复杂度 O(n)
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for (int i = 0; i < size; i++)
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{
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int size = nums.Length;
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// 辅助哈希表,空间复杂度 O(n)
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Dictionary<int, int> dic = new();
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// 单层循环,时间复杂度 O(n)
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for (int i = 0; i < size; i++)
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if (dic.ContainsKey(target - nums[i]))
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{
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if (dic.ContainsKey(target - nums[i]))
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{
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return new int[] { dic[target - nums[i]], i };
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}
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dic.Add(nums[i], i);
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return new int[] { dic[target - nums[i]], i };
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}
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return new int[0];
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dic.Add(nums[i], i);
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}
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return new int[0];
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}
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```
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