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<li>递归求解规模减小一半的子问题，可能为 <span class="arithmatex">\(f(i, m-1)\)</span> 或 <span class="arithmatex">\(f(m+1, j)\)</span> 。</li>
<li>循环第 <code>1.</code> , <code>2.</code> 步，直至找到 <code>target</code> 或区间为空时返回。</li>
</ol>
<p>下图展示了在数组中二分查找元素 <span class="arithmatex">\(6\)</span> 的分治过程。</p>
<p>图 12-4 展示了在数组中二分查找元素 <span class="arithmatex">\(6\)</span> 的分治过程。</p>
<p><img alt="二分查找的分治过程" src="../binary_search_recur.assets/binary_search_recur.png" /></p>
<p align="center"> 图：二分查找的分治过程 </p>
<p align="center"> 图 12-4 &nbsp; 二分查找的分治过程 </p>
<p>在实现代码中，我们声明一个递归函数 <code>dfs()</code> 来求解问题 <span class="arithmatex">\(f(i, j)\)</span> 。</p>
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