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Fix multilingual content typos (#1958)

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Yudong Jin
2026-08-18 03:08:23 +08:00
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en/docs/chapter_heap/build_heap.md
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@@ -31,7 +31,7 @@ It's worth noting that **since leaf nodes have no children, they are naturally v
Next, let's attempt to derive the time complexity of this second heap construction method.
- Assuming the complete binary tree has $n$ nodes, then the number of leaf nodes is $(n + 1) / 2$, where $/$ is floor division. Therefore, the number of nodes that need heapification is $(n - 1) / 2$.
- Assuming the complete binary tree has $n$ nodes, then the number of leaf nodes is $(n + 1) / 2$, where $/$ is floor division. Therefore, the number of nodes that need heapification is $n / 2$.
- In the top-to-bottom heapify process, each node can sink at most to a leaf node, so the maximum number of iterations is the height of the binary tree, $\log n$.
Multiplying these two together, we get a time complexity of $O(n \log n)$ for the heap construction process. **However, this estimate is not accurate because it doesn't account for the property that binary trees have far more nodes at lower levels than at upper levels**.