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Re-translate the Japanese version (#1871)
* Retranslate Japanese docs with GPT-5.4 * Retranslate Japanese code with GPT-5.4
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@@ -0,0 +1,92 @@
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=begin
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File: space_complexity.rb
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Created Time: 2024-03-30
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Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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=end
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require_relative '../utils/list_node'
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require_relative '../utils/tree_node'
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require_relative '../utils/print_util'
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### 関数 ###
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def function
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# 何らかの処理を行う
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0
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end
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### 定数階 ###
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def constant(n)
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# 定数、変数、オブジェクトは O(1) の空間を占める
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a = 0
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nums = [0] * 10000
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node = ListNode.new
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# ループ内の変数は O(1) の空間を占める
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(0...n).each { c = 0 }
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# ループ内の関数は O(1) の空間を占める
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(0...n).each { function }
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end
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### 線形階 ###
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def linear(n)
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# 長さ n のリストは O(n) の空間を使用
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nums = Array.new(n, 0)
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# 長さ n のハッシュテーブルは O(n) の空間を使用
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hmap = {}
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for i in 0...n
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hmap[i] = i.to_s
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end
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end
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# ## 線形階(再帰実装)###
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def linear_recur(n)
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puts "再帰 n = #{n}"
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return if n == 1
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linear_recur(n - 1)
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end
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### 平方階 ###
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def quadratic(n)
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# 二次元リストは O(n^2) の空間を使用
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Array.new(n) { Array.new(n, 0) }
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end
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# ## 平方階(再帰実装)###
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def quadratic_recur(n)
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return 0 unless n > 0
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# 配列 nums の長さは n, n-1, ..., 2, 1
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nums = Array.new(n, 0)
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quadratic_recur(n - 1)
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end
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# ## 指数階(満二分木を構築)###
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def build_tree(n)
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return if n == 0
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TreeNode.new.tap do |root|
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root.left = build_tree(n - 1)
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root.right = build_tree(n - 1)
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end
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end
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### Driver Code ###
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if __FILE__ == $0
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n = 5
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# 定数階
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constant(n)
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# 線形階
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linear(n)
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linear_recur(n)
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# 二乗階
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quadratic(n)
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quadratic_recur(n)
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# 指数オーダー
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root = build_tree(n)
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print_tree(root)
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end
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