Bug fixes and improvements (#1298)

* Fix is_empty() implementation in the stack and queue chapter

* Update en/CONTRIBUTING.md

* Remove "剩余" from the state definition of knapsack problem

* Sync zh and zh-hant versions

* Update the stylesheets of code tabs

* Fix quick_sort.rb

* Fix TS code

* Update chapter_paperbook

* Upload the manuscript of 0.1 section

* Fix binary_tree_dfs.rb

* Bug fixes

* Update README

* Update README

* Update README

* Update README.md

* Update README

* Sync zh and zh-hant versions

* Bug fixes
This commit is contained in:
Yudong Jin
2024-04-22 02:26:32 +08:00
committed by GitHub
parent 74f1a63e8c
commit f616dac7da
61 changed files with 1606 additions and 145 deletions
@@ -0,0 +1,154 @@
=begin
File: quick_sort.rb
Created Time: 2024-04-01
Author: Cy (3739004@gmail.com), Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
=end
### 快速排序類別 ###
class QuickSort
class << self
### 哨兵劃分 ###
def partition(nums, left, right)
# 以 nums[left] 為基準數
i, j = left, right
while i < j
while i < j && nums[j] >= nums[left]
j -= 1 # 從右向左找首個小於基準數的元素
end
while i < j && nums[i] <= nums[left]
i += 1 # 從左向右找首個大於基準數的元素
end
# 元素交換
nums[i], nums[j] = nums[j], nums[i]
end
# 將基準數交換至兩子陣列的分界線
nums[i], nums[left] = nums[left], nums[i]
i # 返回基準數的索引
end
### 快速排序類別 ###
def quick_sort(nums, left, right)
# 子陣列長度不為 1 時遞迴
if left < right
# 哨兵劃分
pivot = partition(nums, left, right)
# 遞迴左子陣列、右子陣列
quick_sort(nums, left, pivot - 1)
quick_sort(nums, pivot + 1, right)
end
nums
end
end
end
### 快速排序類別(中位數最佳化)###
class QuickSortMedian
class << self
### 選取三個候選元素的中位數 ###
def median_three(nums, left, mid, right)
# 選取三個候選元素的中位數
_l, _m, _r = nums[left], nums[mid], nums[right]
# m 在 l 和 r 之間
return mid if (_l <= _m && _m <= _r) || (_r <= _m && _m <= _l)
# l 在 m 和 r 之間
return left if (_m <= _l && _l <= _r) || (_r <= _l && _l <= _m)
return right
end
### 哨兵劃分(三數取中值)###
def partition(nums, left, right)
### 以 nums[left] 為基準數
med = median_three(nums, left, (left + right) / 2, right)
# 將中位數交換至陣列最左斷
nums[left], nums[med] = nums[med], nums[left]
i, j = left, right
while i < j
while i < j && nums[j] >= nums[left]
j -= 1 # 從右向左找首個小於基準數的元素
end
while i < j && nums[i] <= nums[left]
i += 1 # 從左向右找首個大於基準數的元素
end
# 元素交換
nums[i], nums[j] = nums[j], nums[i]
end
# 將基準數交換至兩子陣列的分界線
nums[i], nums[left] = nums[left], nums[i]
i # 返回基準數的索引
end
### 快速排序 ###
def quick_sort(nums, left, right)
# 子陣列長度不為 1 時遞迴
if left < right
# 哨兵劃分
pivot = partition(nums, left, right)
# 遞迴左子陣列、右子陣列
quick_sort(nums, left, pivot - 1)
quick_sort(nums, pivot + 1, right)
end
nums
end
end
end
### 快速排序類別(尾遞迴最佳化)###
class QuickSortTailCall
class << self
### 哨兵劃分 ###
def partition(nums, left, right)
# 以 nums[left]為基準數
i = left
j = right
while i < j
while i < j && nums[j] >= nums[left]
j -= 1 # 從右向左找首個小於基準數的元素
end
while i < j && nums[i] <= nums[left]
i += 1 # 從左向右找首個大於基準數的元素
end
# 元素交換
nums[i], nums[j] = nums[j], nums[i]
end
# 將基準數交換至兩子陣列的分界線
nums[i], nums[left] = nums[left], nums[i]
i # 返回基準數的索引
end
### 快速排序(尾遞迴最佳化)
def quick_sort(nums, left, right)
# 子陣列長度不為 1 時遞迴
while left < right
# 哨兵劃分
pivot = partition(nums, left, right)
# 對兩個子陣列中較短的那個執行快速排序
if pivot - left < right - pivot
quick_sort(nums, left, pivot - 1)
left = pivot + 1 # 剩餘未排序區間為 [pivot + 1, right]
else
quick_sort(nums, pivot + 1, right)
right = pivot - 1 # 剩餘未排序區間為 [left, pivot - 1]
end
end
end
end
end
### Driver Code ###
if __FILE__ == $0
# 快速排序
nums = [2, 4, 1, 0, 3, 5]
QuickSort.quick_sort(nums, 0, nums.length - 1)
puts "快速排序完成後 nums = #{nums}"
# 快速排序(中位基準數最佳化)
nums1 = [2, 4, 1, 0, 3, 5]
QuickSortMedian.quick_sort(nums1, 0, nums1.length - 1)
puts "快速排序(中位基準數最佳化)完成後 nums1 = #{nums1}"
# 快速排序(尾遞迴最佳化)
nums2 = [2, 4, 1, 0, 3, 5]
QuickSortTailCall.quick_sort(nums2, 0, nums2.length - 1)
puts "快速排序(尾遞迴最佳化)完成後 nums2 = #{nums2}"
end