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@@ -676,11 +676,20 @@ comments: true
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=== "Ruby"
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```ruby title="my_heap.rb"
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[class]{MaxHeap}-[func]{left}
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### 獲取左子節點的索引 ###
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def left(i)
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2 * i + 1
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end
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[class]{MaxHeap}-[func]{right}
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### 獲取右子節點的索引 ###
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def right(i)
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2 * i + 2
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end
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[class]{MaxHeap}-[func]{parent}
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### 獲取父節點的索引 ###
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def parent(i)
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(i - 1) / 2 # 向下整除
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end
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```
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=== "Zig"
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@@ -817,7 +826,10 @@ comments: true
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=== "Ruby"
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```ruby title="my_heap.rb"
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[class]{MaxHeap}-[func]{peek}
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### 訪問堆積頂元素 ###
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def peek
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@max_heap[0]
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end
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```
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=== "Zig"
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@@ -1211,9 +1223,27 @@ comments: true
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=== "Ruby"
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```ruby title="my_heap.rb"
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[class]{MaxHeap}-[func]{push}
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### 元素入堆積 ###
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def push(val)
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# 新增節點
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@max_heap << val
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# 從底至頂堆積化
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sift_up(size - 1)
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end
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[class]{MaxHeap}-[func]{sift_up}
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### 從節點 i 開始,從底至頂堆積化 ###
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def sift_up(i)
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loop do
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# 獲取節點 i 的父節點
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p = parent(i)
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# 當“越過根節點”或“節點無須修復”時,結束堆積化
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break if p < 0 || @max_heap[i] <= @max_heap[p]
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# 交換兩節點
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swap(i, p)
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# 迴圈向上堆積化
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i = p
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end
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end
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```
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=== "Zig"
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@@ -1649,7 +1679,7 @@ comments: true
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// 交換根節點與最右葉節點(交換首元素與尾元素)
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self.swap(0, self.size() - 1);
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// 刪除節點
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let val = self.max_heap.remove(self.size() - 1);
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let val = self.max_heap.pop().unwrap();
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// 從頂至底堆積化
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self.sift_down(0);
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// 返回堆積頂元素
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@@ -1767,9 +1797,37 @@ comments: true
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=== "Ruby"
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```ruby title="my_heap.rb"
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[class]{MaxHeap}-[func]{pop}
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### 元素出堆積 ###
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def pop
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# 判空處理
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raise IndexError, "堆積為空" if is_empty?
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# 交換根節點與最右葉節點(交換首元素與尾元素)
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swap(0, size - 1)
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# 刪除節點
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val = @max_heap.pop
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# 從頂至底堆積化
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sift_down(0)
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# 返回堆積頂元素
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val
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end
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[class]{MaxHeap}-[func]{sift_down}
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### 從節點 i 開始,從頂至底堆積化 ###
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def sift_down(i)
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loop do
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# 判斷節點 i, l, r 中值最大的節點,記為 ma
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l, r, ma = left(i), right(i), i
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ma = l if l < size && @max_heap[l] > @max_heap[ma]
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ma = r if r < size && @max_heap[r] > @max_heap[ma]
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# 若節點 i 最大或索引 l, r 越界,則無須繼續堆積化,跳出
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break if ma == i
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# 交換兩節點
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swap(i, ma)
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# 迴圈向下堆積化
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i = ma
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end
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end
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```
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=== "Zig"
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@@ -437,7 +437,28 @@ comments: true
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=== "Ruby"
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```ruby title="top_k.rb"
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[class]{}-[func]{top_k_heap}
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### 基於堆積查詢陣列中最大的 k 個元素 ###
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def top_k_heap(nums, k)
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# 初始化小頂堆積
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# 請注意:我們將堆積中所有元素取反,從而用大頂堆積來模擬小頂堆積
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max_heap = MaxHeap.new([])
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# 將陣列的前 k 個元素入堆積
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for i in 0...k
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push_min_heap(max_heap, nums[i])
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end
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# 從第 k+1 個元素開始,保持堆積的長度為 k
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for i in k...nums.length
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# 若當前元素大於堆積頂元素,則將堆積頂元素出堆積、當前元素入堆積
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if nums[i] > peek_min_heap(max_heap)
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pop_min_heap(max_heap)
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push_min_heap(max_heap, nums[i])
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end
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end
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get_min_heap(max_heap)
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end
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```
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=== "Zig"
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