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@@ -230,20 +230,17 @@ comments: true
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```csharp title="quick_sort.cs"
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/* 元素交换 */
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void swap(int[] nums, int i, int j)
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{
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void swap(int[] nums, int i, int j) {
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int tmp = nums[i];
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nums[i] = nums[j];
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nums[j] = tmp;
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}
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/* 哨兵划分 */
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int partition(int[] nums, int left, int right)
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{
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int partition(int[] nums, int left, int right) {
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// 以 nums[left] 作为基准数
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int i = left, j = right;
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while (i < j)
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{
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while (i < j) {
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while (i < j && nums[j] >= nums[left])
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j--; // 从右向左找首个小于基准数的元素
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while (i < j && nums[i] <= nums[left])
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@@ -459,8 +456,7 @@ comments: true
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```csharp title="quick_sort.cs"
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/* 快速排序 */
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void quickSort(int[] nums, int left, int right)
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{
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void quickSort(int[] nums, int left, int right) {
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// 子数组长度为 1 时终止递归
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if (left >= right)
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return;
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@@ -815,8 +811,7 @@ comments: true
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```csharp title="quick_sort.cs"
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/* 选取三个元素的中位数 */
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int medianThree(int[] nums, int left, int mid, int right)
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{
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int medianThree(int[] nums, int left, int mid, int right) {
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// 此处使用异或运算来简化代码
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// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
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if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
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@@ -828,16 +823,14 @@ comments: true
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}
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/* 哨兵划分(三数取中值) */
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int partition(int[] nums, int left, int right)
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{
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int partition(int[] nums, int left, int right) {
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// 选取三个候选元素的中位数
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int med = medianThree(nums, left, (left + right) / 2, right);
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// 将中位数交换至数组最左端
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swap(nums, left, med);
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// 以 nums[left] 作为基准数
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int i = left, j = right;
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while (i < j)
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{
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while (i < j) {
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while (i < j && nums[j] >= nums[left])
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j--; // 从右向左找首个小于基准数的元素
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while (i < j && nums[i] <= nums[left])
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@@ -1063,21 +1056,16 @@ comments: true
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```csharp title="quick_sort.cs"
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/* 快速排序(尾递归优化) */
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void quickSort(int[] nums, int left, int right)
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{
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void quickSort(int[] nums, int left, int right) {
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// 子数组长度为 1 时终止
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while (left < right)
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{
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while (left < right) {
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// 哨兵划分操作
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int pivot = partition(nums, left, right);
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// 对两个子数组中较短的那个执行快排
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if (pivot - left < right - pivot)
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{
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if (pivot - left < right - pivot) {
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quickSort(nums, left, pivot - 1); // 递归排序左子数组
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left = pivot + 1; // 剩余待排序区间为 [pivot + 1, right]
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}
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else
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{
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} else {
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quickSort(nums, pivot + 1, right); // 递归排序右子数组
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right = pivot - 1; // 剩余待排序区间为 [left, pivot - 1]
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}
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