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Swift

/**
* File: permutations_ii.swift
* Created Time: 2023-04-30
* Author: nuomi1 (nuomi1@qq.com)
*/
/* 回溯算法:全排列 II */
func backtrack(state: inout [Int], choices: [Int], selected: inout [Bool], res: inout [[Int]]) {
// 当状态长度等于元素数量时,记录解
if state.count == choices.count {
res.append(state)
return
}
// 遍历所有选择
var duplicated: Set<Int> = []
for (i, choice) in choices.enumerated() {
// 剪枝:不允许重复选择元素 且 不允许重复选择相等元素
if !selected[i], !duplicated.contains(choice) {
// 尝试:做出选择,更新状态
duplicated.insert(choice) // 记录选择过的元素值
selected[i] = true
state.append(choice)
// 进行下一轮选择
backtrack(state: &state, choices: choices, selected: &selected, res: &res)
// 回退:撤销选择,恢复到之前的状态
selected[i] = false
state.removeLast()
}
}
}
/* 全排列 II */
func permutationsII(nums: [Int]) -> [[Int]] {
var state: [Int] = []
var selected = Array(repeating: false, count: nums.count)
var res: [[Int]] = []
backtrack(state: &state, choices: nums, selected: &selected, res: &res)
return res
}
@main
enum PermutationsII {
/* Driver Code */
static func main() {
let nums = [1, 2, 3]
let res = permutationsII(nums: nums)
print("输入数组 nums = \(nums)")
print("所有排列 res = \(res)")
}
}