Files
2023-09-15 02:08:09 +08:00

48 lines
1.5 KiB
Swift

/**
* File: build_tree.swift
* Created Time: 2023-09-02
* Author: nuomi1 (nuomi1@qq.com)
*/
import utils
/* 构建二叉树:分治 */
func dfs(preorder: [Int], inorderMap: [Int: Int], i: Int, l: Int, r: Int) -> TreeNode? {
// 子树区间为空时终止
if r - l < 0 {
return nil
}
// 初始化根节点
let root = TreeNode(x: preorder[i])
// 查询 m ,从而划分左右子树
let m = inorderMap[preorder[i]]!
// 子问题:构建左子树
root.left = dfs(preorder: preorder, inorderMap: inorderMap, i: i + 1, l: l, r: m - 1)
// 子问题:构建右子树
root.right = dfs(preorder: preorder, inorderMap: inorderMap, i: i + 1 + m - l, l: m + 1, r: r)
// 返回根节点
return root
}
/* 构建二叉树 */
func buildTree(preorder: [Int], inorder: [Int]) -> TreeNode? {
// 初始化哈希表,存储 inorder 元素到索引的映射
let inorderMap = inorder.enumerated().reduce(into: [:]) { $0[$1.element] = $1.offset }
return dfs(preorder: preorder, inorderMap: inorderMap, i: 0, l: 0, r: inorder.count - 1)
}
@main
enum BuildTree {
/* Driver Code */
static func main() {
let preorder = [3, 9, 2, 1, 7]
let inorder = [9, 3, 1, 2, 7]
print("前序遍历 = \(preorder)")
print("中序遍历 = \(inorder)")
let root = buildTree(preorder: preorder, inorder: inorder)
print("构建的二叉树为:")
PrintUtil.printTree(root: root)
}
}