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第 8 章 &nbsp;
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第 9 章 &nbsp;
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第 10 章 &nbsp; 搜索
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10.2 &nbsp; 二分查找插入点
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10.3 &nbsp; 二分查找边界
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10.4 &nbsp; 哈希优化策略
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10.5 &nbsp; 重识搜索算法
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第 11 章 &nbsp; 排序
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第 12 章 &nbsp; 分治
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12.1 &nbsp; 分治算法
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12.3 &nbsp; 构建树问题
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第 13 章 &nbsp; 回溯
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第 14 章 &nbsp; 动态规划
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14.2 &nbsp; DP 问题特性
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<h1 id="65">6.5 &nbsp; 练习<a class="headerlink" href="#65" title="Permanent link">&para;</a></h1>
<h2 id="651">6.5.1 &nbsp; 知识巩固<a class="headerlink" href="#651" title="Permanent link">&para;</a></h2>
<h3 id="1">1. &nbsp; 发生哈希冲突后怎样查找<a class="headerlink" href="#1" title="Permanent link">&para;</a></h3>
<p>一个哈希表有 5 个桶,哈希函数为 <span class="arithmatex">\(h(x)=x \bmod 5\)</span>,冲突时把元素依次放进该桶的列表中。
依次插入 <code>[1, 6, 11, 7]</code></p>
<!-- numbered-subquestions -->
<ol>
<li>写出 04 号桶中的内容;</li>
<li>查找 6 时会先进入哪个桶,并依次检查哪些元素?</li>
<li>根据第 1 问写出的桶内容,后插入的元素是否覆盖了先插入的元素?结合这种冲突处理方式说明理由。</li>
</ol>
<details class="success">
<summary>参考答案</summary>
<ol>
<li>
<p>因为 <span class="arithmatex">\(1\bmod5=6\bmod5=11\bmod5=1\)</span>,而 <span class="arithmatex">\(7\bmod5=2\)</span>,各桶为:</p>
<div class="highlight"><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a>0: []
<a id="__codelineno-0-2" name="__codelineno-0-2" href="#__codelineno-0-2"></a>1: [1, 6, 11]
<a id="__codelineno-0-3" name="__codelineno-0-3" href="#__codelineno-0-3"></a>2: [7]
<a id="__codelineno-0-4" name="__codelineno-0-4" href="#__codelineno-0-4"></a>3: []
<a id="__codelineno-0-5" name="__codelineno-0-5" href="#__codelineno-0-5"></a>4: []
</code></pre></div>
</li>
<li>
<p>查找 6 时先进入 1 号桶,再依次比较 1、6,第二次比较时找到目标。</p>
</li>
<li>
<p>哈希值相同只表示它们落入同一个桶,并不表示这些元素相等。链式地址把冲突元素都保存在桶内,
查询时再逐个比较,因此 1、6、11 不会互相覆盖。</p>
</li>
</ol>
</details>
<h3 id="2">2. &nbsp; 哈希表扩容后元素去哪儿<a class="headerlink" href="#2" title="Permanent link">&para;</a></h3>
<p>一个使用链式地址的哈希表原有 5 个桶,哈希函数为 <span class="arithmatex">\(h(x)=x\bmod5\)</span>
<code>[1, 6, 11]</code> 都在 1 号桶中。</p>
<p>现在把哈希表扩容为 7 个桶,哈希函数相应变为 <span class="arithmatex">\(h(x)=x\bmod7\)</span></p>
<!-- numbered-subquestions -->
<ol>
<li>分别计算 1、6、11 的新桶号。</li>
<li>扩容后哪些桶中有元素?</li>
<li>扩容时能否把原来 1 号桶中的列表原样复制到新的 1 号桶?结合第 1、2 问的结果说明理由。</li>
</ol>
<details class="success">
<summary>参考答案</summary>
<ol>
<li>
<p>新桶号分别为:</p>
<ul>
<li><span class="arithmatex">\(1\bmod7=1\)</span></li>
<li><span class="arithmatex">\(6\bmod7=6\)</span></li>
<li><span class="arithmatex">\(11\bmod7=4\)</span></li>
</ul>
</li>
<li>
<p>1 号桶保存 1,4 号桶保存 11,6 号桶保存 6。三个键不再挤在同一个桶中。</p>
</li>
<li>
<p>不能原样复制。桶号由“键对桶数取余”得到。桶数从 5 变成 7 后,同一个键的新桶号可能改变,
因此必须重新计算每个键的位置。若把旧的 1 号桶原样复制过去,之后按新公式查找 6 和 11 时,
会分别前往 6 号桶和 4 号桶,从而找不到它们。</p>
</li>
</ol>
</details>
<h3 id="3-6-11">3. &nbsp; 删除 6 后还能找到 11 吗<a class="headerlink" href="#3-6-11" title="Permanent link">&para;</a></h3>
<p>一个哈希表有 5 个位置,索引为 <code>04</code>,哈希函数为 <span class="arithmatex">\(h(x)=x\bmod5\)</span>
发生冲突时,从哈希函数算出的索引开始,向右寻找第一个空位。</p>
<p>依次插入 <code>[1, 6, 11]</code></p>
<!-- numbered-subquestions -->
<ol>
<li>三个数最终分别放在哪个索引?</li>
<li>查找 11 时,会依次检查哪些索引?</li>
<li>如果删除 6 时直接把它的位置改成“从未使用的空位”,而查找遇到空位就停止,
再查找 11 时会发生什么?这个查找结果是否正确?如果有问题,应怎样避免?</li>
</ol>
<details class="success">
<summary>参考答案</summary>
<ol>
<li>
<p>1 放在索引 1。6 也映射到索引 1,发生冲突后放在索引 2。
11 同样从索引 1 开始,依次跳过已占用的索引 1、2,最终放在索引 3。</p>
</li>
<li>
<p>查找 11 时依次检查索引 <code>1、2、3</code>,在索引 3 找到它。</p>
</li>
<li>
<p>如果把索引 2 改成表示“从未使用”的空位,查找 11 时检查索引 1 后就会在索引 2 停止,
从而错误地认为 11 不存在。删除时应留下“已删除”标记:
查找遇到该标记时继续检查下一个索引(越过索引 4 后回到索引 0),而以后的插入仍可重新使用这个位置。</p>
</li>
</ol>
</details>
<h2 id="652">6.5.2 &nbsp; 编程练习<a class="headerlink" href="#652" title="Permanent link">&para;</a></h2>
<h3 id="1_1">1. &nbsp; 比较两个字符串的字符组成<a class="headerlink" href="#1_1" title="Permanent link">&para;</a></h3>
<p>给定两个只含小写英文字母的字符串 <code>s</code><code>t</code>
可以任意调整 <code>s</code> 中字符的位置,但不能添加、删除或替换字符。</p>
<p>请判断调整后能否得到 <code>t</code>;可以则返回 <code>true</code>,否则返回 <code>false</code>
请使用哈希表记录各字母的出现次数,不对字符串中的字符排序。</p>
<details class="tip">
<summary>解题提示</summary>
<ol>
<li>两个字符串长度不同,它们的字符组成一定不同</li>
<li>用哈希表记录每种字母的数量;扫描 s 时把对应计数加 1</li>
<li>扫描 t 时把对应计数减 1;所有计数最终都为 0,字符组成才相同</li>
</ol>
</details>
<p><a class="rounded-button exercise-button" href="https://leetcode.cn/problems/valid-anagram/" rel="noopener noreferrer" target="_blank">LeetCode</a> <a class="rounded-button exercise-button" href="https://leetcode.cn/problems/valid-anagram/solutions/2362065/242-you-xiao-de-zi-mu-yi-wei-ci-ha-xi-bi-cch7/" rel="noopener noreferrer" target="_blank">题目解析</a></p>
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